An SAT prep course claims to increase student scores by more than 60 points, on average. To test this claim, 9 students who have previously taken the SAT are randomlychosen to take the prep course. Their SAT scores before and after completing the prep course are listed in the following table. Test the claim at the 0.02 level ofsignificance assuming that the population distribution of the paired differences is approximately normal. Let scores before completing the prep course be Population 1and let scores after completing the prep course be Population 2.BeforePrepCourseAfterPrepCourse1470 1230 11301600 1280 1150SAT Scores1390 1380 1380 1380 1060 13501630 14201420 1570 1320 1490Copy DataStep 2 of 3: Compute the value of the test statistic. Round your answer to three decimal places.

From the provided information,n = 9α = 0.02The difference table is as follow:d = population 1 -…

Answered: An SAT prep course claims to increase…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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The mean number of sick days an employee takes per year is believed to be about 10. Members of a personnel department do not believe this figure. They randomly survey 8 employees. The number of sick days they took for the past year are as follows: 10; 5; 13; 3; 11; 8; 6; 9. Let X = the number of sick days they took for the past year. Should the personnel team believe that the mean number is about 10? Conduct a hypothesis test at the 5% level.Note: If you are using a Student's t-distribution for the problem, you may assume that the underlying population is normally distributed. (In general, you must first prove that assumption, though.) What is the test statistic? (If using the z distribution round your answers to two decimal places, and if using the t distribution round your answers to three decimal places.) t = Construct a 95% confidence interval for the true mean. Sketch the graph of the situation. Label the point estimate and the lower and upper bounds of the confidence…
Which of these scenarios means that a pretest-posttest design with a non-equivalent control group is not suitable? Select all that apply. O a. All of the available participants will be receiving the intervention at the same time. O b. Authors want to examine for any trends in the data over time. O c. The participants were placed into the experimental and control groups by natural circumstances rather than random assignment. O d. Authors want to compare averages between two groups before and after the intervention using an ANOVA.
UBS Wealth Management UK periodically ask their customers to evaluate their financial consultants and services. The higher the customer rating, the better the perceived service. The maximum rating is 7. Independent samples of two financial consultants are given below. Consultant A has 10 years' experience, Consultant B has 1 years' experience. Use α = 0.05 and test to see whether the consultant with more experience has the higher population mean service rating. Consultant A Consultant B N1 = 16 N2 = 10 Mean1 = 6.82 Mean2 = 6.25 S1= 0.64 S2 = 0.75 State the null and alternative hypothesis, Compute the value of the test statistic. What is the p-value? What is your conclusion?
According to the Carnegie unit system, the recommended number of hours students should study per unit is 2. Are statistics students' study hours more than the recommended number of hours per unit? The data show the results of a survey of 11 statistics students who were asked how many hours per unit they studied. Assume a normal distribution for the population. 2, 2.9, 4.5, 0.7, 3.3, 4.5, 4.2, 1.2, 0.9, 1.8, 2.8 What can be concluded at the αα = 0.05 level of significance? The p-value = (Please show your answer to 4 decimal places. Based on this, we should Select an answer fail to reject accept reject the null hypothesis Thus, the final conclusion is that ... The data suggest the populaton mean is significantly more than 2 at αα = 0.05, so there is enough evidence to conclude that the population mean study time per unit for statistics students is more than 2. The data suggest the population mean is not significantly more than 2 at αα = 0.05, so there is enough evidence to…
Each person in random samples of 227 male and 293 female working adults living in a certain town in Canada was asked how long, in minutes, his or her typical daily commute was. Is there enough evidence to show that there is a difference in mean commute times for male and female working residents of this town? (Use males females) Male Female Sample size X S Sample size x S 227 30.2 24.0 293 27.9 24.3 Find the test statistic. (Round your answer to two decimal places.) Find the df. (Round your answer down to the nearest whole number.) df= Use technology to find the P-value. (Round your answer to four decimal places.) P-value= Is there enough evidence to show that there is a difference in mean commute times for male and female working residents of this town? Use a significance level of 0.05. Yes No
The work week for adults in the US that work full time is normally distributed with a mean of 47 hours. A newly hired engineer at a start-up company believes that employees at start-up companies work more on average then most working adults in the US. She asks 12 engineering friends at start-ups for the lengths in hours of their work week. Their responses are shown in the table below. Test the claim using a 10% level of significance. Hours 47 47 55 51 48 65 51 52 50 49 51 54 What are the correct hypotheses? Ho: Select an answer ✓ ? ✓ Ha: Select an answer ✓ Test Statistic= hours Based on the hypotheses, find the following: p-value= hours (Give answer to at least 4 decimal places.) (Give answer to at least 4 decimal places).
Do rats take less time on average than hamsters to travel through a maze? The table below shows the times in seconds that the rats and hamsters took. Rats: 36, 35, 22, 42, 25, 14, 31, 14 Hamsters: 41, 37, 12, 46, 39, 46, 38, 45, 27, 29 Assume that both populations follow a normal distribution. What can be concluded at the a = 0.05 level of significance level of significance? For this study, we should use Select an answer a. The null and alternative hypotheses would be: Ho: Select an answer v Select an answer v Select an answer v (please enter a decimal) H: Select an answer v Select an answer v Select an answer v (Please enter a decimal) b. The test statistic (please show your answer to 3 decimal places.) c. The p-value = (Please show your answer to 4 decimal places.) d. The p-value is ? ♥ a e. Based on this, we should Select an answer f. Thus, the final conclusion is that ... the null hypothesis. O The results are statistically insignificant at a = 0.05, so there is statistically…
Does the type of instruction in a college statistics class (either lecture or self-paced) influence students’ performance, as measured by the number of quizzes successfully completed during the semester? Twelve students were recruited for the study. Students received the lecture instruction or a self-paced instruction. The total number of quizzes completed during teach type of instruction appear below.
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