f. Thus, the final conclusion is that ...O The results are statistically insignificant at a = 0.05, so there is statistically significantevidence to conclude that the population mean time to complete the maze for rats is equal tothe population mean time to complete the maze for hamsters.%3DO The results are statistically significant at a = 0.05, so there is sufficient evidence to concludethat the mean time to complete the maze for the eight rats is less than the mean time tocomplete the maze for the ten hamsters.O The results are statistically significant at a = 0.05, so there is sufficient evidence to concludethat the population mean time to complete the maze for rats is less than the population meantime to complete the maze for hamsters.O The results are statistically insignificant at a = 0.05, so there is insufficient evidence toconclude that the population mean time to complete the maze for rats is less than thepopulation mean time to complete the maze for hamsters.!!g. Interpret thep-value in the context of the study.O If the sample mean time to complete the maze for the 8 rats is the same as the sample meantime to complete the maze for the 10 hamsters and if another 8 rats and 10 hamsters areobserved then there would be a 5.18% chance of concluding that the mean time to completethe maze for the 8 rats is at least 8.6 seconds less than the mean time to complete the mazefor the 10 hamsters.O There is a 5.18% chance of a Type I error.O There is a 5.18% chance that the mean time to complete the maze for the 8 rats is at least 8.6seconds less than the mean time to complete the maze for the 10 hamsters.O If the population mean time to complete the maze for rats is the same as the population meantime to complete the maze for hamsters and if another 8 rats and 10 hamsters are observedthen there would be a 5.18% chance that the mean time to complete the maze for the 8 ratswould be at least 8.6 seconds less than the mean time to complete the maze for the 10hamsters.h. Interpret the level of significance in the context of the study.O If the population mean time to complete the maze for rats is the same as the population meantime to complete the maze for hamsters and if another 8 rats and 10 hamsters are observedthen there would be a 5% chance that we would end up falsely concluding that the populationmean time to complete the maze for rats is less than the population mean time to completethe maze for hamstersO There is a 5% chance that the rat will eat the hamster.O If the population mean time to complete the maze for rats is the same as the population meantime to complete the maze for hamsters and if another 8 rats and 10 hamsters are observed,then there would be a 5% chance that we would end up falsely concluding that the samplemean time to complete the maze for these 8 rats and 10 hamsters differ from each other,O There is a 5% chance that the population mean time to complete the maze for rats andhamsters is the same.P Type here to searchhp Do rats take less time on average than hamsters to travel through a maze? The table below shows the timesin seconds that the rats and hamsters took.Rats: 36, 35,22,42,25,14,31,14Hamsters: 41, 37,12,46,39,46,38,45,27,29Assume that both populations follow a normal distribution. What can be concluded at the a = 0.05 levelof significance level of significance?For this study, we should use Select an answera. The null and alternative hypotheses would be:Ho: Select an answer vSelect an answer v Select an answer v (please enter a decimal)H: Select an answer vSelect an answer vSelect an answer v (Please enter a decimal)b. The test statistic(please show your answer to 3 decimal places.)c. The p-value =(Please show your answer to 4 decimal places.)d. The p-value is ? ♥ ae. Based on this, we should Select an answerf. Thus, the final conclusion is that ...the null hypothesis.O The results are statistically insignificant at a = 0.05, so there is statistically significantevidence to conclude that the population mean time to complete the maze for rats is equal tothe population mean time to complete the maze for hamsters.O The results are statistically significant at a = 0.05, so there is sufficient evidence to concludethat the mean time to complete the maze for the eight rats is less than the mean time tocomplete the maze for the ten hamsters.O The results are statistically significant at a = 0.05, so there is sufficient evidence to concludethat the population mean time to complete the maze for rats is less than the population meantime to complete the maze for hamsters.O The results are statistically insignificant at a = 0.05, so there is insufficient evidence toconclude that the ponuulation mean time to comolete the maze for rats is less than theP Type here to searchhp

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Answered: Do rats take less time on average than…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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In a study on the effect of sleep deprivation on pilots’ flight performance, 10 pilots were tested on a flight simulation after 12 hours of sleep deprivation, tested again after 24 hours, and tested once more after 36 hours. The dependent variable was the number of flight decision errors made by the pilots during each test. 1. Which statistical test should be used to analyze the data? Be specific. Why should this particular test be used? What are the degrees of freedom for the comparison distribution? What is the critical value of the test statistic (a = .05)? You run the test and find that F = 9.92. What do you || %3D obt conclude about the effect of sleep deprivation on flight performance?
Do rats take the same amount of time on average than hamsters to travel through a maze? The table below shows the times in seconds that the rats and hamsters took. 32, 14, 23, 27, 36 1, 42, Rats: 31, 38, 48, 24, 37, 36, 45, 24, Hamsters: 39, 40 Assume that both populations follow a normal distribution. What can be concluded at the a = 0.01 level of significance level of significance? For this study, we should use Select an answer a. The null and alternative hypotheses would be: Select an answer Но: Select an answer > Select an answer O (please enter a decimal) Select an answer (Please enter a decimal) Select an answer (please show b. The test statistic ? O your answer to 3 decimal places.) (Please show your answer to c. The p-value = 4 decimal places.)
What is the likely media when the mean is 9 the sample variance is 7.31 and the skew is 1.04
The average house has 11 paintings on its walls. Is the mean larger for houses owned by teachers? The data show the results of a survey of 14 teachers who were asked how many paintings they have in their houses. Assume that the distribution of the population is normal. 12, 13, 12, 12, 12, 11, 13, 12, 13, 11, 10, 12, 11, 13 What can be concluded at the a = 0.05 level of significance? a. For this study, we should use Select an answer b. The null and alternative hypotheses would be: Но: Select an answer H1: Select an answer c. The test statistic ? ▼ (please show your answer to 3 decimal places.) d. The p-value = (Please show your answer to 4 decimal places.) e. The p-value is (? v f. Based on this, we should | Select an answer the null hypothesis. g. Thus, the final conclusion is that ... The data suggest the population mean is not significantly more than 11 at a = 0.05, so there is sufficient evidence to conclude that the population mean number of paintings that are in teachers' houses…
3. Of all the pupils in a particular school, 45 % go to school by bus. In a random sample of 30 pupils, calculate the mean and variance number of pupils that go to school by bus.
the distribution of sample means consists of the
pls help Eight car dealerships reported the number of cars they sold last month. Car Dealership Number of Cars Sold GMC 84 Chevrolet 81 Nissan 92 Toyota 92 Ford 95 Honda 94 Hyundai 80 Acura 72 What is the upper and lower quartile of this set of data? lower quartile: 80.5upper quartile: 93 lower quartile: 88upper quartile: 93 lower quartile: 80.5upper quartile: 88 lower quartile: 72upper quartile: 95
MEASURES OF CENTRAL TENDENCY AND VARIABILITY.1. Suppose two classes achieved the following grades on a math test,Class A: 64, 70, 73, 77, 85, 90, 94Class B: 74, 75, 75, 76, 79, 80, 94 In each class, find the mean, median, mode, range, interquartile range, Variance,Standard Deviation, coefficient of variance Which class is better?
Texts Sent Per Day and Favorite Way to Communicate Exercise 1.24 introduces a survey given to a sample of high school seniors in Pennsylvania. Two of the variables in the survey are TextsSent, the number of text messages sent per day, and Communicate, the student’s favorite way to communicate with friends (App, In person, Phone, or Text). The data are stored in PASeniors.Use technology to find the summary statistics for each of the four categories. 1. Which group has the largest mean number of texts sent? 2. Which group has the smallest? Use technology to conduct an ANOVA test. 3. What is the F-statistic? (round to two decimal places)4. What is the p-value? (round to four decimal places) 5. What is the conclusion of the test? Communicate TextsSent Text 500 Text 30 Phone 50 App 50 In person 500 Text 15 In person 100 In person 0…
For the last 12 years, Colin has contributed $110 each month into a retirement savings account. If the account earns 7% per year compounded monthly what is the balance of the account at the end of the 12th year?
An amusement park keeps track of the percentage of individuals with season passes according to age category. An independent tourist company would like to show that this distribution of age category for individuals buying season passes is different from what the amusement park claims. The tourist company randomly sampled 200 individuals entering the park with a season pass and recorded the number of individuals within each age category. Age Category Child (under 13 years old) Teen (13 to 19 years old) Adult (20 to 55 years old) Senior (56 years old and over) Number of Individuals 56 86 44 14 The tourist company will use the data to test the amusement park’s claim, which is reflected in the following null hypothesis. H0:pchild=0.23H0:pchild=0.23, pteen=0.45pteen=0.45, padult=0.20padult=0.20, and psenior=0.12psenior=0.12. What inference procedure will the company use to investigate whether or not the distribution of age category for individuals with season passes is…
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