An object of mass m = 1.00 kg is observed to have an acceleration of a with a magnitude of 24.2 m/s2 in a direction 6 = 59.5° east of north. The figure below shows a view of the object from above. The force F, acting on the object has a magnitude of 12.3 N and is directed north. Determine the magnitude and direction of the force F, acting on the object. magnitude N direction ---Select--- m F

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### Physics Problem on Forces and Acceleration

An object of mass \( m = 1.00 \, \text{kg} \) is observed to have an acceleration \( \vec{a} \) with a magnitude of \( 24.2 \, \text{m/s}^2 \) in a direction \( \theta = 59.5^\circ \) east of north. The figure below shows a view of the object from above. The force \( \vec{F}_2 \) acting on the object has a magnitude of \( 12.3 \, \text{N} \) and is directed north. Determine the magnitude and direction of the force \( \vec{F}_1 \) acting on the object.

**Input Fields:**
- **Magnitude:** [Text box for input] N
- **Direction:** [Drop-down menu for direction selection]

#### Diagram Explanation:
- **m:** A square representing the object.
- **\( \vec{F}_2 \):** An upward arrow (blue) originating from the object, representing the force acting north with a magnitude of \( 12.3 \, \text{N} \).
- **\( \vec{F}_1 \):** A rightward arrow (blue) originating from the object, representing the force whose magnitude and direction need to be determined.
- **\( \vec{a} \):** A diagonal arrow (purple) at an angle \( \theta \) of \( 59.5^\circ \) east of north, representing the acceleration of the object with a magnitude of \( 24.2 \, \text{m/s}^2 \).

Use the given data and figure to solve for the required force \( \vec{F}_1 \), considering the provided information and applying relevant physics principles such as Newton's Second Law of Motion and vector resolution.
Transcribed Image Text:### Physics Problem on Forces and Acceleration An object of mass \( m = 1.00 \, \text{kg} \) is observed to have an acceleration \( \vec{a} \) with a magnitude of \( 24.2 \, \text{m/s}^2 \) in a direction \( \theta = 59.5^\circ \) east of north. The figure below shows a view of the object from above. The force \( \vec{F}_2 \) acting on the object has a magnitude of \( 12.3 \, \text{N} \) and is directed north. Determine the magnitude and direction of the force \( \vec{F}_1 \) acting on the object. **Input Fields:** - **Magnitude:** [Text box for input] N - **Direction:** [Drop-down menu for direction selection] #### Diagram Explanation: - **m:** A square representing the object. - **\( \vec{F}_2 \):** An upward arrow (blue) originating from the object, representing the force acting north with a magnitude of \( 12.3 \, \text{N} \). - **\( \vec{F}_1 \):** A rightward arrow (blue) originating from the object, representing the force whose magnitude and direction need to be determined. - **\( \vec{a} \):** A diagonal arrow (purple) at an angle \( \theta \) of \( 59.5^\circ \) east of north, representing the acceleration of the object with a magnitude of \( 24.2 \, \text{m/s}^2 \). Use the given data and figure to solve for the required force \( \vec{F}_1 \), considering the provided information and applying relevant physics principles such as Newton's Second Law of Motion and vector resolution.
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