The diagram below is a top-down view of two children pulling a 11.6-kg sled along the snow. The first child exerts a force of F1 = 10 N at an angle ?1 = 45° counterclockwise from the positive x direction. The second child exerts a force of F2 = 6 N at an angle ?2 = 30° clockwise from the positive x direction. (A) Find the magnitude (in N) and direction of the friction force acting on the sled if it moves with constant velocity. magnitude = ? direction (counterclockwise from the +x-axis) = ? (B) What is the coefficient of kinetic friction between the sled and the ground? (C) What is the magnitude of the acceleration (in m/s2) of the sled if F1 is doubled and F2 is halved in magnitude?

The diagram below is a top-down view of two children pulling a 11.6-kg sled along the snow. The first child exerts a force of F1 = 10 N at an angle ?1 = 45° counterclockwise from the positive x direction. The second child exerts a force of F2 = 6 N at an angle ?2 = 30° clockwise from the positive x direction. (A) Find the magnitude (in N) and direction of the friction force acting on the sled if it moves with constant velocity. magnitude = ? direction (counterclockwise from the +x-axis) = ? (B) What is the coefficient of kinetic friction between the sled and the ground? (C) What is the magnitude of the acceleration (in m/s2) of the sled if F1 is doubled and F2 is halved in magnitude?

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A block with a mass of m = 32 kg rests on a frictionless surface and is subject to two forces acting on it. The first force is directed in the negative x-direction with a magnitude of F1. The second has a magnitude of F2 and acts on the body at an angle θ = 23° measured from horizontal, as shown.Write an expression for the magnitude of the normal force, FN, acting on the block, in terms of F2 and the other variables of the problem. Assume that the surface it rests on is rigid. The two forces change such that F1 = 11 N and F2 = 21.5 N. Based on this change, the block may no longer be in static equilibrium. Find the block's acceleration in the x-direction, ax, in meters per second squared.
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A block having a mass of m = 19.5 kg is suspended via two cables as shown in the figure. The angles shown in the figure are as follows: α = 12° and β = 35°. We will label the tension in Cable 1 as T1 and the tension in Cable 2 as T2 a)Write an expression for the sum of forces in the x direction in terms of T1, T2, m, g, α, and β. Use the specified coordinate system. b)Write an expression for the sum of forces in the y direction in terms of T1, T2, m, g, α, and β. Use the specified coordinate system. c)Solve for the numeric value of T1, in newtons. d)Solve for the numeric value of T2,in newtons
The diagram below is a top-down view of two children pulling a 13.2-kg sled along the snow. The first child exerts a force of |F¡| = 12.0 N at an angle 0, = 45.0° counterclockwise from the positive x direction. The second child exerts a force of F2| = 6.00 N at an angle 02 = 30.0° clockwise from the positive x direction. We use a right-handed coordinate system with the +x axis and +z axis in the horizontal plane, and the +y axis out of the page. F2 (a) Find the friction force acting on the sled if it moves with constant velocity. Express your answer in vector form. f = N (b) What is the coefficient of kinetic friction between the sled and the ground? (c) What is the acceleration of the sled if F, is doubled and F2 is halved in magnitude? Express your answer in vector form. m/s? a =
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A horizontal force, F1 = 55 N, and a force, F2 = 17 N acting at an angle of 0 to the horizontal, are applied to a block of mass m = 3.9 kg. The coefficient of kinetic friction between the block and the surface is uk 0.2. The block is moving to the right. = Randomized Variables F₁ = 55 N F₂=17 N m = 3.9 kg o vi ble. on d ed ed FN=46.72 (b) Solve numerically for the magnitude of acceleration of the block, a in m/s², if 0 = 30°. (a) Solve numerically for the magnitude of the normal force, FN in Newtons, that acts on the block if 0 = 30°. ✓ Correct! a = 15.487 tan() П acos() E 14 sinh() 1 * 1 tanh() cotanh() Degrees O Radians 2 0 VO BACKSPACE sin() cos() cotan() asin() atan() acotan() cosh() Submit Hint . Feedback 7 85 9 6 3 I give up! • DEL HOME ← END y. CLEAR X Hk m 0
In the figure below, a box of Cheerios (mass mc = 1.5 kg) and a box of Wheaties (mass mw = 2.7 kg) are accelerated across a horizontal surface by a horizontal force F applied to the Cheerios box. The magnitude of the frictional force on the Cheerios box is 2.0 N, and the magnitude of the frictional force on the Wheaties box is 4.1 N. If the magnitude of F is 12 N, what is the magnitude of the force on the Wheaties box from the Cheerios box? |---Select--- mc Mw
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