LEARN MORE REMARKS It's interesting that the final result depends only on the coefficient of static friction. Notice also how similar Equations (1) and (2) are to the equations developed in previous problems. Recognizing such patterns is key to solving problems successfully. QUESTION A larger static friction constant would result in a: (Select all that apply.) O larger component of normal force at the maximum angle. O larger component of gravitational force along the ramp at the maximum angle. O smaller component of gravitational force along the ramp at the maximum angle. O larger maximum angle. smaller maximum angle.

College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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Write Newton's laws for a static system
(1) EF, = mg sin 0 – µ̟n = 0
in component form. The gravity force
has two components.
(2) EF, = n - mg cos 0 = 0
Rearrange Equation (2) to get an
n = mg cos e
expression for the normal force n.
Substitute the expression for n into
EF, = mg sin 0 – µ̟mgcos 0 = 0 → tan 0 =µ,
Equation (1) and solve for tan 0.
Apply the inverse tangent function to
tan 0 = 0.350 → 0 = tan 1 (0.350) = 19.3°
get the answer.
LEARN MORE
REMARKS It's interesting that the final result depends only on the coefficient of static friction. Notice
also how similar Equations (1) and (2) are to the equations developed in previous problems. Recognizing
such patterns is key to solving problems successfully.
QUESTION A larger static friction constant would result in a: (Select all that apply.)
O larger component of normal force at the maximum angle.
O larger component of gravitational force along the ramp at the maximum angle.
smaller component of gravitational force along the ramp at the maximum angle.
O larger maximum angle.
O smaller maximum angle.
Transcribed Image Text:Write Newton's laws for a static system (1) EF, = mg sin 0 – µ̟n = 0 in component form. The gravity force has two components. (2) EF, = n - mg cos 0 = 0 Rearrange Equation (2) to get an n = mg cos e expression for the normal force n. Substitute the expression for n into EF, = mg sin 0 – µ̟mgcos 0 = 0 → tan 0 =µ, Equation (1) and solve for tan 0. Apply the inverse tangent function to tan 0 = 0.350 → 0 = tan 1 (0.350) = 19.3° get the answer. LEARN MORE REMARKS It's interesting that the final result depends only on the coefficient of static friction. Notice also how similar Equations (1) and (2) are to the equations developed in previous problems. Recognizing such patterns is key to solving problems successfully. QUESTION A larger static friction constant would result in a: (Select all that apply.) O larger component of normal force at the maximum angle. O larger component of gravitational force along the ramp at the maximum angle. smaller component of gravitational force along the ramp at the maximum angle. O larger maximum angle. O smaller maximum angle.
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