The following four forces act on a 50.0 kg object:F₁ = 300 N east₹ 2 = 700 N north₹ 3 = 600 N westF 4 = 300 N southWhat is the acceleration of the object?14.0 m/s² in a direction 53.1º north of westO10.0 m/s2in a direction 53.1° north of west14.0 m/s2in a direction 36.9° north of westO 10.0 m/s² in a direction 36.9° north of west

Answered: Image /qna-images/answer/be9f598a-3936-47b5-85ea-09a1a4f1564e.jpg

The following four forces act on a 50.0 kg object: F₁ = 300 N east ₹ 2 = 700 N north ₹ 3 = 600 N west F 4 = 300 N south What is the acceleration of the object? 14.0 m/s² in a direction 53.1° north of west O 10.0 m/s2 in a direction 53.1° north of west 14.0 m/s2 in a direction 36.9° north of west 10.0 m/s² in a direction 36.9° north of west O

The following four forces act on a 50.0 kg object: F₁ = 300 N east ₹ 2 = 700 N north ₹ 3 = 600 N west F 4 = 300 N south What is the acceleration of the object? 14.0 m/s² in a direction 53.1° north of west O 10.0 m/s2 in a direction 53.1° north of west 14.0 m/s2 in a direction 36.9° north of west 10.0 m/s² in a direction 36.9° north of west O

College Physics

11th Edition

ISBN:9781305952300

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter1: Units, Trigonometry. And Vectors

Section: Chapter Questions

Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...

See similar textbooks

Related questions

Q: A cart of mass 8.00 kg was moved by applying two constant forces. Force 1 is 28.0 N at 42.0°, and…

A: Given: mass of cart, m = 8.0 kgForce, F1 = 28.0 N at 42°Force, F2 = 13 N at 110°

Q: Only two forces act on an object (mass=3.61 kg), as in the drawing. Find (a) the magnitude and (b)…

A: Given data: The mass m=3.61 kg The force Fx=40.0 N The force Fy=60.0 N

Q: Two blocks are connected by a massless, stretchless rope passing over a massless, frictionless…

Q: One end of a rope is tied to a 11 kg hanging weight. The rope goes over a pulley and the other end…

Q: Only two forces act on an object (mass = 4.58 kg), as in the drawing. Find the (a) magnitude and (b)…

A: Given data: Two forces are acting on the object Mass (m) = 4.58 kg F1 = 40.0 N and F2 = 60.0 N…

Q: An object with a mass of 2.0 kg is dropped and takes 3.0 s to hit the ground. Then another object…

Q: Three forces F1 = (-1.5i – 0.8j + 0.7k) N and F2 = (-0.7i + 1.2j) N, and F3= (8.0i + 6.0j + 5.0k) m…

A: Given,

Q: Two forces (F, and F2) act on an object, as shown above. Force vector F, has a magnitude of F1-5.7 N…

Q: Only two forces act on an object (mass=3.83 kg), as in the drawing. Find (a) the magnitude and (b)…

Q: A block of mass 22 kg moves up a 32 degree inclined plane by being pulled by a string attached to a…

Q: 2. What is the magnitude of the resultant of the three forces acting at point X? SON X 9.00

A: "Since you have asked multiple questions, as per instructions to us, we will solve the first…

Q: 5) An object weighing 500 N is suspended from two ropes that are attached to the ceiling 1.5 m…

A: The problem asks us to calculate the tension in each rope of an object weighing 500 N and suspended…

Q: A block of mass 22 kg moves up a 32 degree inclined plane by being pulled by a string attached to a…

Q: Two horizontal forces, P and Q, are acting on a block that is placed on a table. We know that P…

Q: A 125 kg body sits at rest until 3 forces act up the body: F1 = 24.5 N @ 0o, F2 = 38.0 N @ 160o,…

Q: Two forces F, = -8.40i + 4.30j and F, = 7.50i + 5.30j are acting on an object with a mass of m =…

Q: Two packages at UPS start sliding down the 20° ramp shown in the figure. Package A has a mass of…

Q: As you will see in a later chapter, forces are vector quantities, and the total force on an object…

Q: Suppose a body has a force of 12 pounds acting on it to the right, 25 pounds acting on it upward,…

A: Given forcesF1 = 12 lb ( right )F2 = 25 lb ( up )F3 = 7 lb ( 45 degrees )

Q: An object is moving to the west at a constant speed. Three forces are exerted on the object. One…

A: The force acting on the object in the north direction is F1 = 10 N. The force acting on the object…

Q: Two horizontal forces, P and Q, are acting on a block that is placed on a table. We know that P =…

A: Given: The mass of the object is 5.1 kg. P→=-2.1i^+4.25k^ N The velocity of the object is constant.

Concept explainers

Electric Charges and Fields

One of the fundamental properties is the electromagnetic property. Charge cannot be destroyed by any process and this contributes formally to the law of charge conservation.

Question

The following four forces act on a 50.0 kg object:
F₁ = 300 N east
₹ 2 = 700 N north
₹ 3 = 600 N west
F 4 = 300 N south
What is the acceleration of the object?
14.0 m/s² in a direction 53.1º north of west
O
10.0 m/s2
in a direction 53.1° north of west
14.0 m/s2
in a direction 36.9° north of west
O 10.0 m/s² in a direction 36.9° north of west

Expert Solution

This question has been solved!

Explore an expertly crafted, step-by-step solution for a thorough understanding of key concepts.

This is a popular solution!

SEE SOLUTION Check out a sample Q&A here

Step 1

VIEW

Step 2

VIEW

Trending now

This is a popular solution!

Step by step

Solved in 2 steps with 3 images

SEE SOLUTION Check out a sample Q&A here

Knowledge Booster

Learn more about

Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, physics and related others by exploring similar questions and additional content below.

Similar questions

While two forces act on it, a particle is to move at the constant velocity = (3.58 m/s) -(-3.26 m/s). One of the forces is F1 = (1.88 N) + (-5.85 N). What is the other force? Number i + i j Units
A force ofF1= 50.0 N is directed at an angle of 60° above the x-axis. A second force of F2 = 50.0 N is directed at an angle of 60.0° below the x-axis.= 50.0 N is directed at an angle of 60.0° below the x-axis. What is the vector sum of these two forces?
An object has a velocity (4.69 m/s)i + (-4.4 m/s)j + (4.73 m/s)k. In a time of 5.5 s its velocity becomes (-2.22 m/s)i + (0.00 m/s)j + (4.73 m/s)k. 1) If the mass of the object is 3.31 kg, what is the magnitude of the net force on the object, in N, during the 5.5 s? Assume the acceleration is constant.
The force F has a magnitude of 770 N. Express F as a vector in terms of the unit vectors i and j. Identify the x and y scalar components of F. Assume F-770 N, 8-23° Answers: F- i i+ i j) N Fx- i N Fy- i N
M // 124 N at a downward angle 0 40° You are pushing a block with force F from the horizontal and your friend is pulling the same block with force F2 162 N horizontally in the same direction. The block has mass m = 53.0 kg and is moving with acceleration a in the direction of the exerted force F2. If the coefficient of kinetic friction uk .250 between the block and the floor, what is the magnitude of acceleration đ that the block experiences?
Three forces acting on an object are given by F₁ = (-1.95î + 6.60ĵ) N, F₂ = (4.651 – 1.85ĵ) N, and F3 = (-43.51) N. The object experiences an acceleration of magnitude 3.65 m/s². (a) What is the direction of the acceleration? O (counterclockwise from the +x-axis) (b) What is the mass of the object? kg (c) If the object is initially at rest, what is its speed after 18.0 s? m/s (d) What are the velocity components of the object after 18.0 s? (Let the velocity be denoted by v.) î+ î) m/s
In (Figure 1), F={300i-100j+550k}NF= (300i-100j+550k)N. Determine the magnitude of the projection of the force FF acting along the cable BA◆◆. Express your answer to three significant figures and include the appropriate units. Figure 2m 6m 1 of 1 3m
Two forces FA and FB are applied to an object whose mass is 15.1 kg. The larger force is FA. When both forces point due east, the object's acceleration has a magnitude of 0.561 m/s². However, when FA points due east and FB points due west, the acceleration is 0.328 m/s², due east. Find (a) the magnitude of FA and (b) the magnitude of Fg. (a) Number i (b) Number i Units Units + ➜
Find the magnitude of the friction force when e = 20° and P = 600 N. 1.2 kN Hly = 0.35 Hk = 0.25 O 143.4 N O 153.4 N O 163.4 N O 173.4 N