A cart of mass 8.00 kg was moved by applying two constant forces. Force 1 is 28.0 N at 42.0°, and Force 2 is 13.0 N at 110°. Initially, the cart has a velocity of (3.50 i +2.20 j) m/s. a. Express the two forces in in unit-vector notation. Ans. F = (20.81 i+ 18.74 j)N, F, =(-4.45 i+ 12.22 j)N b. Find the total force exerted on the cart. Ans. EF = (16.36 i + 30.96 j)N or 35.02 N c. Find the angle at which the total force is applied. Ans. 62.15º d. What is the acceleration of the cart? Ans. å = (2.05 i + 3.87 j)" or 4.38 EERIN

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A cart of mass 8.00 kg was moved by applying two constant forces. Force 1 is 28.0 N at
42.0°, and Force 2 is 13.0 N at 110°. Initially, the cart has a velocity of (3.50 i +2.20 j)
m/s.
a. Express the two forces in in unit-vector notation.
Ans. F = (20.81 i+ 18.74 j)N, F, =(-4.45 i+ 12.22 j)N
b. Find the total force exerted on the cart.
Ans. EF = (16.36 i + 30.96 j)N or 35.02 N
c. Find the angle at which the total force is applied. Ans. 62.15º
d. What is the acceleration of the cart? Ans. å = (2.05 i + 3.87 j)" or 4.38
EERIN
Transcribed Image Text:A cart of mass 8.00 kg was moved by applying two constant forces. Force 1 is 28.0 N at 42.0°, and Force 2 is 13.0 N at 110°. Initially, the cart has a velocity of (3.50 i +2.20 j) m/s. a. Express the two forces in in unit-vector notation. Ans. F = (20.81 i+ 18.74 j)N, F, =(-4.45 i+ 12.22 j)N b. Find the total force exerted on the cart. Ans. EF = (16.36 i + 30.96 j)N or 35.02 N c. Find the angle at which the total force is applied. Ans. 62.15º d. What is the acceleration of the cart? Ans. å = (2.05 i + 3.87 j)" or 4.38 EERIN
Expert Solution
Step 1

Given:

mass of cart, m = 8.0 kg
Force, F1 = 28.0 N at 42°
Force, F2 = 13 N at 110° 

Step 2

Physics homework question answer, step 2, image 1

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