M F2 124 N at a downward angle 0 You are pushing a block with force F1 from the horizontal and your friend is pulling the same block with force F2 162 N horizontally in the same direction. The block has mass m = and is moving with acceleration a in the direction of the exerted force F2. If the coefficient of kinetic friction µk : is the magnitude of acceleration ã that the block experiences? 40° 53.0 kg .250 between the block and the floor, what
M F2 124 N at a downward angle 0 You are pushing a block with force F1 from the horizontal and your friend is pulling the same block with force F2 162 N horizontally in the same direction. The block has mass m = and is moving with acceleration a in the direction of the exerted force F2. If the coefficient of kinetic friction µk : is the magnitude of acceleration ã that the block experiences? 40° 53.0 kg .250 between the block and the floor, what
College Physics
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ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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Transcribed Image Text:M
//
124 N at a downward angle 0
40°
You are pushing a block with force F
from the horizontal and your friend is pulling the same block with force F2
162 N horizontally in the same direction. The block has mass m =
53.0 kg
and is moving with acceleration a in the direction of the exerted force F2. If the
coefficient of kinetic friction uk
.250 between the block and the floor, what
is the magnitude of acceleration đ that the block experiences?
Expert Solution
Step 1
The force due to kinetic friction experienced by a body in motion is given by , where
= coefficient of kinetic friction,
N = normal force acting on the body.
The relation between Force and acceleration experienced by a body is given by Newton's second law.
F = ma, where
m = mass of the body,
F = net force exerted on the body
a = acceleration experienced by the body.
We equate the forces in the horizontal direction and also equate the forces in the vertical direction to find the acceleration.
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