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An experiment was run to compare four types of metal plating on the resistance of a sword to rust, namely: the Corporeal Cooling, Divine Varnishing, Bejeweled, and Spray Painting methods. The sample sizes for each method were (respectively) 10, 23, 12, and 14, the means were 42.1, 40.7, 38, and 41, and the standard deviations were 6.5, 6.1, 7.3, and 5.9. The overall average was 40.46, and the total sample size was 59. Assuming equal variances and normality test if the metal plating changes resistance to rust. The following equations may (or may not) be helpful:

An experiment was run to compare four types of metal plating on the resistance of a sword to rust, namely: the Corporeal Cooling, Divine Varnishing, Bejeweled, and Spray Painting methods. The sample sizes for each method were (respectively) 10, 23, 12, and 14, the means were 42.1, 40.7, 38, and 41, and the standard deviations were 6.5, 6.1, 7.3, and 5.9. The overall average was 40.46, and the total sample size was 59. Assuming equal variances and normality test if the metal plating changes resistance to rust. The following equations may (or may not) be helpful:

MATLAB: An Introduction with Applications
MATLAB: An Introduction with Applications
6th Edition
ISBN:9781119256830
Author:Amos Gilat
Publisher:Amos Gilat
Chapter1: Starting With Matlab
Section: Chapter Questions
Problem 1P
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An experiment was run to compare four types of metal plating on the resistance of a sword to rust, namely: the Corporeal Cooling, Divine Varnishing, Bejeweled, and Spray Painting methods. The sample sizes for each method were (respectively) 10, 23, 12, and 14, the means were 42.1, 40.7, 38, and 41, and the standard deviations were 6.5, 6.1, 7.3, and 5.9. The overall average was 40.46, and the total sample size was 59. Assuming equal variances and normality test if the metal plating changes resistance to rust.

The following equations may (or may not) be helpful:

10·(42.1−40.46)2+23·(40.7−40.46)2+12·(38−40.46)2+14·(41−40.46)2=104.9224

 

(10−1)6.52+(23−1)6.12+(12−1)7.32+(14−1)5.92=2237.59

 

(10−6.5)2+(23−6.1)2+(12−7.3)2+(14−5.9)2=385.56

 

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