An experiment is conducted to determine whether intensive tutoring (covering a great deal of material in a fixed amount of time) is more effective than paced tutoring (covering less material in the same amount of time). Two randomly chosen groups are tutored separately and then administered proficiency tests. The data collected and summarized below: Group1 (the intensive group) consisted of 12 students and resulted in an average grade of 46.31 with a standard deviation of 6.44. group 2 (the paced group) consisted of 10 students and resulted in an average grade of 42.79 with a standard deviation of 7.52. Assume that the population variances of both groups are different. To test the claim that intensive tutoring is more effective than paced tutoring, find the degree of freedom and the critical value , and make a decision. df= 17 t critical value to 05 = 1.739 Fail to reject HO. df= 17 t critical value to 05 = 1.782 Fail to reject HO. df= 17 t critical value to.025 = 1.986 Fail to reject HO. df= 17 t critical value to.025 = 1.986 Reject H0. df= 17 t critical value to.05 = 1.739 Reject HO.
An experiment is conducted to determine whether intensive tutoring (covering a great deal of material in a fixed amount of time) is more effective than paced tutoring (covering less material in the same amount of time). Two randomly chosen groups are tutored separately and then administered proficiency tests. The data collected and summarized below: Group1 (the intensive group) consisted of 12 students and resulted in an average grade of 46.31 with a standard deviation of 6.44. group 2 (the paced group) consisted of 10 students and resulted in an average grade of 42.79 with a standard deviation of 7.52. Assume that the population variances of both groups are different. To test the claim that intensive tutoring is more effective than paced tutoring, find the degree of freedom and the critical value , and make a decision. df= 17 t critical value to 05 = 1.739 Fail to reject HO. df= 17 t critical value to 05 = 1.782 Fail to reject HO. df= 17 t critical value to.025 = 1.986 Fail to reject HO. df= 17 t critical value to.025 = 1.986 Reject H0. df= 17 t critical value to.05 = 1.739 Reject HO.
MATLAB: An Introduction with Applications
6th Edition
ISBN:9781119256830
Author:Amos Gilat
Publisher:Amos Gilat
Chapter1: Starting With Matlab
Section: Chapter Questions
Problem 1P
Related questions
Question
Expert Solution
This question has been solved!
Explore an expertly crafted, step-by-step solution for a thorough understanding of key concepts.
This is a popular solution!
Trending now
This is a popular solution!
Step by step
Solved in 3 steps with 5 images
Recommended textbooks for you
MATLAB: An Introduction with Applications
Statistics
ISBN:
9781119256830
Author:
Amos Gilat
Publisher:
John Wiley & Sons Inc
Probability and Statistics for Engineering and th…
Statistics
ISBN:
9781305251809
Author:
Jay L. Devore
Publisher:
Cengage Learning
Statistics for The Behavioral Sciences (MindTap C…
Statistics
ISBN:
9781305504912
Author:
Frederick J Gravetter, Larry B. Wallnau
Publisher:
Cengage Learning
MATLAB: An Introduction with Applications
Statistics
ISBN:
9781119256830
Author:
Amos Gilat
Publisher:
John Wiley & Sons Inc
Probability and Statistics for Engineering and th…
Statistics
ISBN:
9781305251809
Author:
Jay L. Devore
Publisher:
Cengage Learning
Statistics for The Behavioral Sciences (MindTap C…
Statistics
ISBN:
9781305504912
Author:
Frederick J Gravetter, Larry B. Wallnau
Publisher:
Cengage Learning
Elementary Statistics: Picturing the World (7th E…
Statistics
ISBN:
9780134683416
Author:
Ron Larson, Betsy Farber
Publisher:
PEARSON
The Basic Practice of Statistics
Statistics
ISBN:
9781319042578
Author:
David S. Moore, William I. Notz, Michael A. Fligner
Publisher:
W. H. Freeman
Introduction to the Practice of Statistics
Statistics
ISBN:
9781319013387
Author:
David S. Moore, George P. McCabe, Bruce A. Craig
Publisher:
W. H. Freeman