An example of the distortion of the pulse is its separation from the fixed peak value as in the figure below. This is known as bending. The bending is the result of the low frequency cut-off of the amplifier. It is an exponential wave with a transient voltage time constant t=(Ri+Rs)Cc and Vg=Vi(1-exp(t/t)). What is the low cutoff frequency of an amplifier that will amplify 1ms pulses assuming that the bending distortion must be less than 1%?
An example of the distortion of the pulse is its separation from the fixed peak value as in the figure below. This is known as bending. The bending is the result of the low frequency cut-off of the amplifier. It is an exponential wave with a transient voltage time constant t=(Ri+Rs)Cc and Vg=Vi(1-exp(t/t)). What is the low cutoff frequency of an amplifier that will amplify 1ms pulses assuming that the bending distortion must be less than 1%?
Introductory Circuit Analysis (13th Edition)
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ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
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An example of the distortion of the pulse is its separation from the fixed peak value as in the figure below. This is known as bending. The bending is the result of the low frequency cut-off of the amplifier. It is an exponential wave with a transient voltage time constant t=(Ri+Rs)Cc and Vg=Vi(1-exp(t/t)). What is the low cutoff frequency of an amplifier that will amplify 1ms pulses assuming that the bending distortion must be less than 1%?
answer: 1.8kHz, 6.5Hz, 100hz, 1.2kHz, 1.6Hz is one of the answers.
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2.30
rise time
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