An environmental chemist is performing a study of iron in atmospheric particulate measured downwind from a steel mill. She is concerned that wind velocity at the time of measurement may affect the readings. So, she decided to obtain observations on 30 randomly chosen days during the period of peak operation of the mill. She then, compares measurements taken on days when the wind is calm (velocity ≤ 5 knots) with measurements taken on windy days (velocity > 5 knots). The data are presented as the following:
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- Please answer number 17.5. Oxygen demand is a term blologists use to describe the axygen needed by fish and other aquatic organisms for survval. The Environmental Protection Agency conducted a study of a wetland area in Marin County, Californla. In this wetland environment, the mean oxygen demand was u=9.9 mg/L, and a= 1.7 mg/L. (Reference: EPA Report 832-R- 93- 005). Let x be a random varlable that represents oxygen demand in this wetland environment. Assume x has a probability distribution that is approximately normal. a. An oxygen demand below 8 mg/L Indicates that some organisms In the wetland environment may be dying. What is the probability that the oxygen demand will fall below 8 mg/L? b. A high oxygen demand can also indicate trouble. An oxygen demand above 12 mg/L may indicate an overabundance of organisms that endanger some types of plant life. What is the probability that the oxygen demand will exceed 12 mg/L?A weight-loss program wants to test how well their program is working. The company selects a simple random sample of 51 individual that have been using their program for 15 months. For each individual person, the company records the individual's weight when they started the program 15 months ago as an x-value. The subject's current weight is recorded as a y-value. Therefore, a data point such as (205, 190) would be for a specific person and it would indicate that the individual started the program weighing 205 pounds and currently weighs 190 pounds. In other words, they lost 15 pounds. When the company performed a regression analysis, they found a correlation coefficient of r = 0.707. This clearly shows there is strong correlation, which got the company excited. However, when they showed their data to a statistics professor, the professor pointed out that correlation was not the right tool to show that their program was effective. Correlation will NOT show whether or not there is…
- Fill the chi square for Cross 1 and Cross 2 from the following data in the attached image: Cross 1: Phenotypes Ratio Observed Expected (O-E)2/E Totals X2 = Cross 2: Phenotypes Ratio Observed Expected (O-E)2/E Totals X2 =I need the shade of the part of the curve corresponding to the calculation on both. On #1 and #2 since it was given thru this app when I submitted it. Thank youLeo used an analog sensor to measure the temperature of his solar panels. After the experiment, he wants to process the data he obtained. Is he allowed to describe the data by using the measures of central tendency? No, because the data he gathered is qualitative in nature. Yes, because the data he gathered is quantitative in nature. No, because the data the gathered is quantitative in nature. Yes, because the data he gathered is qualitative in nature.
- Please answer number 17.10. 18.30 Temperatures are measured at various points on a heated plate (Table P18.30). Estimate the temperature at (a) x = 4, y = 3.2, and (b) x = 4.3, y = 2.7. TABLE P18.30 Temperature (°C) at various points on a square heated plate. x = 0 x = 2 y = 0 y 2 y = 4 y=6 y 8 100.00 85.00 70.00 55.00 40.00 90.00 64.49 48.90 38.78 35.00 x = 6 70.00 48.15 35.03 30.39 27.07 30.00 25.00 x = 4 80.00 53.50 38.43 x = 8 60.00 50.00 40.00 30.00 20.003. Load the Santa Barbara temperature data using the following com- mands stbarb=read.table ("berkeley.dat")[,3] Since the data is non-stationary, we consider taking difference of stbarb. Create ACF and PACF plots for the differenced data. Do you have an opinion on possible models based only on these plots?
- The desired distance for Flextronchip customers is 0.4 mm between two adjacent pins. Any deviation from this value causes interference. The process of handling complaints costs the firm at approximately $30.00 per chip. The engineers of the firm expect the average customer will be likely to complain when the distance is off target by at least 0.0002 mm. At the factory, the adjustment can be made at a cost of $1.40, which includes the labor to make the adjustment and additional testing. Required: 1. What is the value of k, the cost coefficient, in the Taguchi quality loss function (QLF) based on the above data? 2. Based on a Taguchi quality loss function (QLF), what should the tolerance be before an adjustment is made at the factory? 3. Based on your answer to (requirement 2) above, what are the specification limits (upper and lower) for the production of the product in question? Complete this question by entering your answers in the tabs below. Required 2 Required 3 What is the value…Lecture(8.8): The amount of time people engage in physical activity mat be related to health outcome. Those who report that they spend more than 15 hours are put into one while those who spend less 10 were put into another group. (Those who fall in between 10 and 15 were left out of the study); The reaearcher then ask the participants to wear a monitor for one month. The average time in minutes is recorded and shown below . Is there any evidence that on average people who watch less than 10 hours watching televsion spend more time on physical activity.?. Test the hypotheses at (alpha=0.05) using the 5 step procedure <10 hours 75 63 118 35 82 >15 hours 62 6 78 43 22 33The authors of a paper compared two different methods for measuring body fat percentage. One method uses ultrasound, and the other method uses X-ray technology. The table gives body fat percentages for 16 athletes using each of these methods (a subset of the data given in a graph that appeared in the paper). For purposes of this exercise, you can assume that the 16 athletes who participated in this study are representative of the population of athletes. Athlete 0 Ho: Md = Ha: Md 0 < 0 5 6 7 8 9 10 11 12 13 14 15 16 X-ray 4.75 7.00 9.25 12.00 17.25 29.50 5.50 6.00 8.00 8.50 9.25 11.00 12.00 14.00 17.00 18.00 USE SALT Ultrasound 4.75 4.00 9.00 11.75 17.00 27.75 6.50 6.75 8.75 9.75 9.50 12.00 12.25 15.75 18.00 18.50 X Find the test statistic and P-value. (Use a table or SALT. Round your test statistic to one decimal place and your P-value to three decimal places.) t = P-value = 0.000 Mx-ray ultrasound.)