An electron of energy 5.02 eV come across a 9.54 eV high barrier. Calculate the tunneling probability of the electron for the barrier width of 0.47 nm. (a) 4.21x10- (b) 2.17×105 (c) 1.44 x10 (d) 1.96 x10
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- An electron has a kinetic energy of 13.3 eV. The electron is incident upon a rectangular barrier of height 21.5 eV and width 1.00 nm. If the electron absorbed all the energy of a photon of green light (with wavelength 546 nm) at the instant it reached the barrier, by what factor would the electron's probability of tunneling through the barrier increase?For a quantum particle in a scattering state as it interacts a certain potential, the general expressions for the transmission and reflection coefficients are given by T = Jtrans Jinc R = | Jref Jinc (1) where Jinc, Jref, Jtrans are probability currents corresponding to the incident, reflected, and transmitted plane waves, respectively. (a). potential For the particle incident from the left to the symmetric finite square well -Vo; a < x < a, V(x) = 0 ; elsewhere, show that B Ꭲ ; R = A AAn electron with an energy of 8.0eV is incident on a potential barrier which is 9.2eV high and 0.25 nm wide. (a) What is the probability that the electron will pass through the barrier? (b) What is the probability that the electron will be reflected? (c) What is the wavelength of the electron before it encounters the barrier? (d) What is the wavelength of the transmitted electron?
- The wave function W(x,t)=Ax^4 where A is a constant. If the particle in the box W is normalized. W(x)=Ax^4 (A x squared), for 0<=x<=1, and W(x) = 0 anywhere. A is a constant. Calculate the probability of getting a particle for the range x1 = 0 to x2 = 1/3 a. 1 × 10^-5 b. 2 × 10^-5 c. 3 × 10^-5 d. 4 × 10^-5The quantum mechanical tunneling process occurs if an electron is incident on a potential barrier of finite width a and finite height Uo. Calculate the transmission probability for this case assuming a barrier width a=1.4 nm and a barrier height Uo=2.6eV assuming that the energy of the electron is E=2.2eV. Give your result in % and round it off to two decimal places, i.e. the nearest hundredths. U(x) Uo 0 < E < Uo E 01 aAn electron with an initial kinetic energy of 1.542 eV (in a region with 1.095 eV potential energy) is incident on a potential step (extending from x=0 to ∞) to V=2.381 eV. What is the transmission probability (in %)? FYI: If we had a travelling wave arriving at a similar potential DROP, then k1 (for x<0) would be real and the symmetry of R=(k1-k2)2/(k1+k2)2 implies reflection/transmission are the same as a potential RISE with the same energies but k1 and k2 swapped.
- Consider a particle moving in a one-dimensional box with walls at x = -L/2 and L/2. (a) Write the wavefunction and probability density for the state n=1. (b) If the particle has a potential barrier at x =0 to x = L/4 (where L = 10 angstroms) with a height of 10.0 eV, what would be the transmission probability of the electrons at the n = 1 state? (c) Compare the energy of the particle at the n= 1 state to the energy of the oscillator at its first excited state.= = An electron having total energy E 4.60 eV approaches a rectangular energy barrier with U■5.10 eV and L-950 pm as shown in the figure below. Classically, the electron cannot pass through the barrier because E < U. Quantum-mechanically, however, the probability of tunneling is not zero. Energy E U 0 i (a) Calculate this probability, which is the transmission coefficient. (Use 9.11 x 10-31 kg for the mass of an electron, 1.055 x 10-34] s for h, and note that there are 1.60 x 10-19 J per eV.) (b) To what value would the width L of the potential barrier have to be increased for the chance of an incident 4.60-eV electron tunneling through the barrier to be one in one million? nmA 1.2 eV electron has a 10^-4 probability of tunneling through a 2.3 eV potential barrier. What is the probability of a 1.2 eV proton tunneling through the same barrier?
- The wavefunction for a quantum particle tunnelling through a potential barrier of thickness L has the form ψ(x) = Ae−Cx in the classically forbidden region where A is a constant and C is given by C^2 = 2m(U − E) /h_bar^2 . (a) Show that this wavefunction is a solution to Schrodinger’s Equation. (b) Why is the probability of tunneling through the barrier proportional to e ^−2CL?A particle is in the ground state of an inifite square well with walls at x = 0 and x = a. Suddenly the right wall moves from x = a to x = 2a. If the energy of the particle is measured after the wall expansion, what will be the most probable value of the probability of getting this result