An electron with an initial kinetic energy of 1.542 eV (in a region with 1.095 eV potential energy) is incident on a potential step (extending from x=0 to ∞) to V=2.381 eV. What is the transmission probability (in %)? FYI: If we had a travelling wave arriving at a similar potential DROP, then k1 (for x<0) would be real and the symmetry of R=(k1-k2)2/(k1+k2)2 implies reflection/transmission are the same as a potential RISE with the same energies but k1 and k2 swapped.

An electron with an initial kinetic energy of 1.542 eV (in a region with 1.095 eV potential energy) is incident on a potential step (extending from x=0 to ∞) to V=2.381 eV. What is the transmission probability (in %)? FYI: If we had a travelling wave arriving at a similar potential DROP, then k1 (for x<0) would be real and the symmetry of R=(k1-k2)2/(k1+k2)2 implies reflection/transmission are the same as a potential RISE with the same energies but k1 and k2 swapped.

Similar questions

Q.4. Imagine that a particle is coming from left with finite energy E and encountered a potential V(x) = Vo (> E) at origin for x20 (as shown below in the figure). Prove that if Vo goes to infinity then wave function goes to zero in the region x 20. IF Vo X-0
An electron with an initial kinetic energy of 2.069 eV (in a region with zero potential energy) is incident on a potential step (extending from x=0 to ∞) to V=4.233 eV. The wave is completely reflected, but what is the 1/e depth, in pm, to which the exponentially decaying probability function in the x>0 zone after the step reaches?
Example 6. A particle of mass 'm’ is moving in a one-dimensional box defined by the potential V = 0, 0sxsa and V = o othcrwise. Estimate the ground state energy using the trial function y (x) = Ax(a-x), OSx
A particle is confined to a one dimensional box with boundaries at x=0 and x-1. The wave function of the particle within the box boundaries is V(x) 2100 (- x + ) and zero V 619 everywhere else. What is the probability of finding the particle between x=0 and x=0.621? Do not enter your final answer as a percentage, but rather a number between 0 and 1. For instance, if you get that the probability is 20%, enter 0.2.
6QM Please answer question throughly and detailed.
An electron has a kinetic energy of 13.3 eV. The electron is incident upon a rectangular barrier of height 21.5 eV and width 1.00 nm. If the electron absorbed all the energy of a photon of green light (with wavelength 546 nm) at the instant it reached the barrier, by what factor would the electron's probability of tunneling through the barrier increase?
The general solution of the Schrodinger equation for a particle confined in an infinite square-well potential (where V = 0) of width L is w(x)= C sin kx + Dcos kx V2mE k where C and D are constants, E is the energy of the particle and m is the mass of the particle. Show that the energy E of the particle inside the square-well potential is quantised.
An electron is trapped in a region between two infinitely high energy barriers. In the region between the barriers the potential energy of the electron is zero. The normalized wave function of the electron in the region between the walls is ψ(x) = Asin(bx), where A=0.5nm1/2 and b=1.18nm-1. What is the probability to find the electron between x = 0.99nm and x = 1.01nm.
A neutron of mass m of energy E a,V(x) = Vo ) II. Estimate the kinetic energy of the neutron when they reach region III.
= = An electron having total energy E 4.60 eV approaches a rectangular energy barrier with U■5.10 eV and L-950 pm as shown in the figure below. Classically, the electron cannot pass through the barrier because E < U. Quantum-mechanically, however, the probability of tunneling is not zero. Energy E U 0 i (a) Calculate this probability, which is the transmission coefficient. (Use 9.11 x 10-31 kg for the mass of an electron, 1.055 x 10-34] s for h, and note that there are 1.60 x 10-19 J per eV.) (b) To what value would the width L of the potential barrier have to be increased for the chance of an incident 4.60-eV electron tunneling through the barrier to be one in one million? nm
Calculate the tunneling probability when the kinetic energy of the particle is 0.2 MeV, the barrier height is 20 MeV, the probability amplitude is 1.95×10¹5 m²¹, and the width of the barrier is 2.97x10-¹8 m. (A) 0.046 (B) 0.156 (C) 0.026 (D) 0.456