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Given 4 = -sin(2x), find 4normatized, the normalized wave function for a 1-dimensional particle-in-a-
box where the box boundaries are at x=0 and x=2n. The potential energy is zero when
0<x< 2n and o outside of these boundaries.
Tnormalized = sin(2x)
Y Ynormalized.
Y is already normalized. That is, Y =
Ynormalized
= -n 2 sin(2x)
sin(2x)
4normalized
2
none are correct

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