A particle is confined to a one dimensional box between x-0 and x=2. It's wave function is given by V (x) =6 for 0
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- A particle is confined to a one dimensional box with boundaries at x=0 and x-1. The wave function of the particle within the box boundaries is V(x) 2100 (- x + ) and zero V 619 everywhere else. What is the probability of finding the particle between x=0 and x=0.621? Do not enter your final answer as a percentage, but rather a number between 0 and 1. For instance, if you get that the probability is 20%, enter 0.2.40. The first excited state of the harmonic oscillator has a wave function of the form y(x) = Axe-ax². (a) Follow theCalculate the uncertainties dr = V(x2) and op = V(p²) for %3D a particle confined in the region -a a, r<-a. %3D
- The wave function W(x,t)=Ax^4 where A is a constant. If the particle in the box W is normalized. W(x)=Ax^4 (A x squared), for 0<=x<=1, and W(x) = 0 anywhere. A is a constant. Calculate the probability of getting a particle for the range x1 = 0 to x2 = 1/3 a. 1 × 10^-5 b. 2 × 10^-5 c. 3 × 10^-5 d. 4 × 10^-5A particle with mass m is in the state .2 mx +iat 2h Y(x,t) = Ae where A and a are positive real constants. Calculate the expectation values of (x).Consider the wavefunction Y(x) = exp(-2a|x|). a) Normalize the above wavefunction. b) Sketch the probability density of the above wavefunction. c) What is the probability of finding the particle in the range 0 < x s 1/a ?