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3n
(2x –), find Ynormalized, the normalized wave function for a 1-dimensional particle-
Given 4 = cos
in-a-box where the box boundaries are at x=0 and x=2. The potential energy is zero when
0<x< 2n and ∞ outside of these boundaries.
Y is already normalized. That is, Y = 4,
normalized.
4'normalized = 1 2 cos (2x – )
пот
2
sin (2x -)
-
4normalized
2
4normalized
sin ( 2x
2
-
none are correct

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