**Problem Statement:**An electron moves in a circular path perpendicular to a magnetic field of magnitude **0.280 T**. If the kinetic energy of the electron is **2.50 × 10⁻¹⁹ J**, find:(a) the speed of the electron (b) the radius of the circular path.---**Solutions:**(a) **The Speed of the Electron:**- Calculated Speed: **7.4e5 m/s** ✔️(b) **The Radius of the Circular Path:**- Calculated Radius: **1.5e-5** ✖️ (Incorrect)

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An electron moves in a circular path perpendicular to a magnetic field of magnitude 0.280 T. If the kinetic energy of the electron is 2.50 x 10-19 J, find the speed of the electron and the radius of the circular path. (a) the speed of the electron 7.4e5 ✔ m/s (b) the radius of the circular path. 1.5e-5 ✓

An electron moves in a circular path perpendicular to a magnetic field of magnitude 0.280 T. If the kinetic energy of the electron is 2.50 x 10-19 J, find the speed of the electron and the radius of the circular path. (a) the speed of the electron 7.4e5 ✔ m/s (b) the radius of the circular path. 1.5e-5 ✓

College Physics

11th Edition

ISBN:9781305952300

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter1: Units, Trigonometry. And Vectors

Section: Chapter Questions

Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...

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