An electron accelerated accelerated from rest through a potential difference of 4000 volts enters the uniform magnetic field of induction 0.01 wb/m² perpendicular to the direction of its motion. Calculate the velocity of an electron and the radius of its path in the magnetic field.
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- (a) At what speed (in m/s) will a proton move in a circular path of the same radius as an electron that travels at 7.80 ✕ 106 m/s perpendicular to the Earth's magnetic field at an altitude where the field strength is 1.20 ✕ 10−5 T? m/s (b) What would the radius (in m) of the path be if the proton had the same speed as the electron? m (c) What would the radius (in m) be if the proton had the same kinetic energy as the electron? m (d) What would the radius (in m) be if the proton had the same momentum as the electron?A proton moving in a circular path perpendicular to a constant magnetic field takes 1.00 µs to complete one revolution. Determine the magnitude of the magnetic field. Taken as q = 1.602x10-19 C and m= 1.67x10-27 kg for proton and r=3.14. 0.0345 T A) 0.0327 T B) 0.0143 T 0.0124 T D) 0.0154 T E)An electron with a velocity of 3.00 x105 m/s is incident normal to the magnetic field lines between the two poles above. In between the magnetic poles, the magnetic field is constant and equal to 0.400 T (a) On the diagram, show with arrows the direction of the magnetic field lines and the magnetic force on the electron. (b) Calculate the magnitude of the magnetic force on the electron.
- A metal rod 40 cm long moves in a plane perpendicular to a magnetic field of 600 G. The velocity of the rod is perpendicular to its length. Find the speed of the rod if the potential difference between the ends is 4 V. m/sElectrons are accelerated from rest in a CRT. These electrons now pass through a magnetic field of 2.70 x 10-2 T and through an electric field of 5.50 x 105 N/C. The fields are perpendicular to each other. If the electrons are not deflected, assuming the electrons are traveling perpendicular to these fields, what is the potential difference across the CRT?A 25 cm rod moves at 5.6 m/s in a plane perpendicular to a magnetic field of strength 0.34 T. The rod, the velocity vector, and the magnetic field vector are mutually perpendicular, as indicated in the accompanying figure. Calculate: (c) The magnitude of the electric field in the rod. (d) What speed would the rod need to move to have 1.0 V potential difference between the two ends?
- A uniform electric field of 7.82 V/m west and a uniform magnetic field of 5.31 T west exist in a region of space. Find the magnitude of the acceleration of an electron moving with velocity 3.2 m/s north in this region. Answer in units of m/s2.Crossed electric and magnetic fields are established over a certain region. The magnetic field is 0.590 T vertically downward. The electric field is 3.48 × 106 V/m horizontally east. An electron, traveling horizontally northward, experiences zero net force from these fields and so continues moving in a straight line. What is the electron’s speed?The magnitude of a magnetic field a distance 3.0 um from a wire is 20.0 * 10^-4 T. How do you determine how much current is flowing through the wire, assuming the wire is the only contributor to the magnetic field.
- An electron is introduced into a uniform magnetic field, Bx = 50.0 μTesla directed at right angles to the electron’s velocity vy = 5 x105 m/s. The electron subsequently moves in a circular path. What is the radius of the circular path?A 71.7 C charge is moving with a velocity of 71.8 m/s in the +x-direction. A magnetic field of 88.8 T is point in the -x-direction. What is the force (in N) on this charge?An electron that is moving through a uniform magnetic field has a velocity v = (44 km/s)i + 31 km/s)j when it experiences a force F = (-3.000×10-15 N)i + (4.258×10-15 N)j due to the magnetic field. If Bx = 0, calculate the magnitude of the magnetic field B. (Tesla = T) 1) what is the magnitude of the magnetic field B? 2) what is By? 3) What is Bz?