An electron moves in a circular path perpendicular to a magnetic field of magnitude 0.29 T. If the kinetic energy of the electron is 2.9  J. (me = 9.109 × 10-31 kg) (a) Find the speed of the electron. 7.98 m 2.523 m 1.784 m 5.642 m (b) Find the radius of the circular path. 1.567 m 11.404 m 0.979 m 4.073 m

College Physics
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Chapter1: Units, Trigonometry. And Vectors
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An electron moves in a circular path perpendicular to a magnetic field of magnitude 0.29 T. If the kinetic energy of the electron is 2.9  J. (me = 9.109 × 10-31 kg)

(a) Find the speed of the electron.

  • 7.98 m
  • 2.523 m
  • 1.784 m
  • 5.642 m

(b) Find the radius of the circular path.

  • 1.567 m
  • 11.404 m
  • 0.979 m
  • 4.073 m
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