**Problem: Motion of Electrons in Crossed Fields****Description:**In a region of space, crossed electric and magnetic fields are present. The magnitudes of these fields are given as:- Electric field (E): 4.65 V/m- Magnetic field (B): 74.5 mT (millitesla)**Question:**At what speed can electrons move perpendicular to both fields without being deflected?**Solution Approach:**To find the speed at which electrons can travel through the crossed electric and magnetic fields without deflection, use the condition for zero net force: the electric force must equal the magnetic force. The relevant equation is:\[ v = \frac{E}{B} \]Where:- \( v \) is the speed of the electrons- \( E \) is the magnitude of the electric field (4.65 V/m)- \( B \) is the magnitude of the magnetic field (74.5 mT converted to T for calculation)Convert B to Tesla:\[ 1 \text{ mT} = 10^{-3} \text{ T} \]\[ B = 74.5 \text{ mT} = 74.5 \times 10^{-3} \text{ T} \]Substitute known values into the formula to find \( v \).

Answered: Crossed electric and magnetic fields…

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