An average force of 4800 N acts on a golf ball for a time interval of 0.003 s. Determine the change in the momentum of the golf ball. The change in the momentum of the golf ball is kg-m/s.

College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
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**Problem Statement:**

An average force of 4800 N acts on a golf ball for a time interval of 0.003 s.

**Task:**

Determine the change in the momentum of the golf ball.

**Question:**

The change in the momentum of the golf ball is ____ kg·m/s.

---

**Explanation:**

To find the change in momentum (\(\Delta p\)) of the golf ball, use the equation derived from Newton's second law:

\[
\Delta p = F \times \Delta t
\]

where:
- \(F\) is the force applied (4800 N),
- \(\Delta t\) is the time interval (0.003 s).

Substitute the given values into the equation:

\[
\Delta p = 4800 \, \text{N} \times 0.003 \, \text{s} = 14.4 \, \text{kg·m/s}
\]

Thus, the change in momentum of the golf ball is 14.4 kg·m/s.
Transcribed Image Text:**Problem Statement:** An average force of 4800 N acts on a golf ball for a time interval of 0.003 s. **Task:** Determine the change in the momentum of the golf ball. **Question:** The change in the momentum of the golf ball is ____ kg·m/s. --- **Explanation:** To find the change in momentum (\(\Delta p\)) of the golf ball, use the equation derived from Newton's second law: \[ \Delta p = F \times \Delta t \] where: - \(F\) is the force applied (4800 N), - \(\Delta t\) is the time interval (0.003 s). Substitute the given values into the equation: \[ \Delta p = 4800 \, \text{N} \times 0.003 \, \text{s} = 14.4 \, \text{kg·m/s} \] Thus, the change in momentum of the golf ball is 14.4 kg·m/s.
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