Two toy cars have a collision and bounce off each other. The first has a mass of 0.5 kg and was initially traveling at 3.5 m/s. The second has a mass of 0.8 kg and had an initial velocity of -2.0 m/s. After colliding the first recoils with a velocity of v1f =-1.19 m/s. After colliding, what is the velocity of the second car? 3.5 m/s 20 m/s m-0.5kg m0.8 kg m0.Skg m 0.8 kg Vy? m-0.Skg m=0.8 kg

College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
icon
Related questions
Question
**Scenario: Collision of Two Toy Cars**

Two toy cars have a collision and bounce off each other. The first car has a mass of 0.5 kg and was initially traveling at 3.5 m/s. The second car has a mass of 0.8 kg and had an initial velocity of -2.0 m/s. After colliding, the first car recoils with a velocity of \( v_{f1} = -1.19 \) m/s. What is the velocity of the second car after the collision?

**Illustrations and Explanation:**

1. **Initial State:**
   - Car 1: Mass = 0.5 kg, Velocity = 3.5 m/s → (towards the right).
   - Car 2: Mass = 0.8 kg, Velocity = -2.0 m/s ← (towards the left).

   Visualization shows two cars on a track, with arrow indicators showing the direction and magnitude of their velocities.

2. **After Collision:**
   - Car 1: Mass = 0.5 kg, Velocity after collision = -1.19 m/s ← (reversing direction).
   - Car 2: Mass = 0.8 kg, Velocity after collision = \( v_{f2} \) (unknown).

   The diagram presents the two cars with updated velocities, illustrating how the first car changes direction after the collision.

**Analysis:**
Using the principle of conservation of momentum:
\[ m_1 \cdot v_{i1} + m_2 \cdot v_{i2} = m_1 \cdot v_{f1} + m_2 \cdot v_{f2} \]

Where:
- \( m_1 = 0.5 \) kg, \( v_{i1} = 3.5 \) m/s
- \( m_2 = 0.8 \) kg, \( v_{i2} = -2.0 \) m/s
- \( v_{f1} = -1.19 \) m/s
- Solve for \( v_{f2} \).

**Conclusion:**
The scenario represents a classic physics problem involving elastic collisions, demonstrating the conservation of momentum and the change in motion based on mass and velocity.
Transcribed Image Text:**Scenario: Collision of Two Toy Cars** Two toy cars have a collision and bounce off each other. The first car has a mass of 0.5 kg and was initially traveling at 3.5 m/s. The second car has a mass of 0.8 kg and had an initial velocity of -2.0 m/s. After colliding, the first car recoils with a velocity of \( v_{f1} = -1.19 \) m/s. What is the velocity of the second car after the collision? **Illustrations and Explanation:** 1. **Initial State:** - Car 1: Mass = 0.5 kg, Velocity = 3.5 m/s → (towards the right). - Car 2: Mass = 0.8 kg, Velocity = -2.0 m/s ← (towards the left). Visualization shows two cars on a track, with arrow indicators showing the direction and magnitude of their velocities. 2. **After Collision:** - Car 1: Mass = 0.5 kg, Velocity after collision = -1.19 m/s ← (reversing direction). - Car 2: Mass = 0.8 kg, Velocity after collision = \( v_{f2} \) (unknown). The diagram presents the two cars with updated velocities, illustrating how the first car changes direction after the collision. **Analysis:** Using the principle of conservation of momentum: \[ m_1 \cdot v_{i1} + m_2 \cdot v_{i2} = m_1 \cdot v_{f1} + m_2 \cdot v_{f2} \] Where: - \( m_1 = 0.5 \) kg, \( v_{i1} = 3.5 \) m/s - \( m_2 = 0.8 \) kg, \( v_{i2} = -2.0 \) m/s - \( v_{f1} = -1.19 \) m/s - Solve for \( v_{f2} \). **Conclusion:** The scenario represents a classic physics problem involving elastic collisions, demonstrating the conservation of momentum and the change in motion based on mass and velocity.
Expert Solution
Step 1

Given

Mass of the first toy car = m1 = 0.5 kg

Mass of the second toy car = m2 = 0.8 kg

Initial velocity of first toy car = v1 = 3.5 m/s

IInitial velocity of second toy car = v2 = -2.0 m/s

Final velocity of first toy car = v1f = -1.19 m/s

WWe have to calculate v2f = ?

 

steps

Step by step

Solved in 2 steps with 1 images

Blurred answer
Similar questions
Recommended textbooks for you
College Physics
College Physics
Physics
ISBN:
9781305952300
Author:
Raymond A. Serway, Chris Vuille
Publisher:
Cengage Learning
University Physics (14th Edition)
University Physics (14th Edition)
Physics
ISBN:
9780133969290
Author:
Hugh D. Young, Roger A. Freedman
Publisher:
PEARSON
Introduction To Quantum Mechanics
Introduction To Quantum Mechanics
Physics
ISBN:
9781107189638
Author:
Griffiths, David J., Schroeter, Darrell F.
Publisher:
Cambridge University Press
Physics for Scientists and Engineers
Physics for Scientists and Engineers
Physics
ISBN:
9781337553278
Author:
Raymond A. Serway, John W. Jewett
Publisher:
Cengage Learning
Lecture- Tutorials for Introductory Astronomy
Lecture- Tutorials for Introductory Astronomy
Physics
ISBN:
9780321820464
Author:
Edward E. Prather, Tim P. Slater, Jeff P. Adams, Gina Brissenden
Publisher:
Addison-Wesley
College Physics: A Strategic Approach (4th Editio…
College Physics: A Strategic Approach (4th Editio…
Physics
ISBN:
9780134609034
Author:
Randall D. Knight (Professor Emeritus), Brian Jones, Stuart Field
Publisher:
PEARSON