A 0.14 kg bead slides on a straight frictionless wire and moves with a velocity of 9.5 m/s to the right. The bead collides with a larger 0.12 kg bead that is initially at rest. After the collision, the smaller bead moves with a velocity of 0.73076923076923 m/s. (use many decimal points in your answer in order to make sure you get it exact) a.What is the large bead's velocity after the collision? b.What is the total kinetic energy of the system of beads after the collision? c.What was the total kinetic energy of the system of beads before the collision?
A 0.14 kg bead slides on a straight frictionless wire and moves with a velocity of 9.5 m/s to the right. The bead collides with a larger 0.12 kg bead that is initially at rest. After the collision, the smaller bead moves with a velocity of 0.73076923076923 m/s. (use many decimal points in your answer in order to make sure you get it exact) a.What is the large bead's velocity after the collision? b.What is the total kinetic energy of the system of beads after the collision? c.What was the total kinetic energy of the system of beads before the collision?
Related questions
Question
A 0.14 kg bead slides on a straight frictionless wire and moves with a velocity of 9.5 m/s to the right. The bead collides with a larger 0.12 kg bead that is initially at rest. After the collision, the smaller bead moves with a velocity of 0.73076923076923 m/s. (use many decimal points in your answer in order to make sure you get it exact)
a.What is the large bead's velocity after the collision?
b.What is the total kinetic energy of the system of beads after the collision?
c.What was the total kinetic energy of the system of beads before the collision?
Expert Solution
This question has been solved!
Explore an expertly crafted, step-by-step solution for a thorough understanding of key concepts.
This is a popular solution!
Trending now
This is a popular solution!
Step by step
Solved in 4 steps