### Physics Problem: Collision of Two Carts#### Problem Statement:A 75.0-kg paint cart with rubber bumpers is rolling at 0.965 m/s to the right. It strikes a second cart with a mass of 85.0 kg that is moving at 1.30 m/s to the left. After the collision, the heavier cart is traveling at 0.823 m/s to the right. What is the velocity of the lighter cart after the collision?#### Diagram Explanation:There is no diagram or graph provided with this problem. However, visualizing the problem could help in understanding the scenario better:- Imagine two carts on a track.- Cart 1 (lighter cart) has a mass of 75.0 kg and is moving to the right with a velocity of 0.965 m/s.- Cart 2 (heavier cart) has a mass of 85.0 kg and is moving to the left with a velocity of 1.30 m/s.- After their collision, Cart 2 moves to the right with a velocity of 0.823 m/s.- We need to determine the velocity of Cart 1 after the collision.#### Solution Approach:To solve this problem, one can use the principles of conservation of momentum, given that no external forces act on the system. The momentum before and after the collision should be equal. 1. **Calculate the total momentum before the collision:**\[ p_{\text{before}} = m_1 \cdot v_{1,\text{initial}} + m_2 \cdot v_{2,\text{initial}} \] Where: - \(m_1 = 75.0 \, \text{kg}\) - \(v_{1,\text{initial}} = 0.965 \, \text{m/s}\) - \(m_2 = 85.0 \, \text{kg}\) - \(v_{2,\text{initial}} = -1.30 \, \text{m/s} \) (since it is moving to the left)2. **Calculate the total momentum after the collision:**\[ p_{\text{after}} = m_1 \cdot v_{1,\text{final}} + m_2 \cdot v_{2,\text{final}} \] Where: - \(v_{2,\text{

The linear momentum of any object having mass m and velocity v is defined as, Now, we know that, if…

A 75.0-kg paint cart with rubber bumpers is rolling 0.965 m/s to the right and strikes a second cart of mass 85.0 kg moving 1.30 m/s to the left. After the collision, the heavier cart is traveling 0.823 m/s to the right. What is the velocity of the lighter cart after the collision?

A 75.0-kg paint cart with rubber bumpers is rolling 0.965 m/s to the right and strikes a second cart of mass 85.0 kg moving 1.30 m/s to the left. After the collision, the heavier cart is traveling 0.823 m/s to the right. What is the velocity of the lighter cart after the collision?

College Physics

11th Edition

ISBN:9781305952300

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter1: Units, Trigonometry. And Vectors

Section: Chapter Questions

Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...

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