An author argues that more American-born baseball players have birth dates in the months immediately following July 31 because that was the age cutoff date for nonschool baseball leagues. The table below lists months of births for a sample ofAmerican-born baseball players and foreign-born baseball players. Using a 0.01 significance level, is there sufficient evidence to warrant rejection of the claim that months of births of baseball players are independent of whether they are born in America? Dothe data appear to support the author's claim?Jan. Feb. March April May June July Aug. Sept. Oct. Nov. Dec.Born in America385 332365344 339 316315 503419433397 368Foreign Born101 818683958359917099104 82.....Identify the null and alternative hypotheses for this test.O A. Ho: The frequency of births is dependent of the month.H1: The frequency of births is independent of the month.O B. Ho: Months of births of baseball players are independent of where they are born.H: Months of births of baseball players are dependent of where they are born.OC. Ho: The frequency of births is independent of the month.H,: The frequency of births is dependent of the month.O D. Ho: Months of births of baseball players are dependent of where they are born.H,: Months of births of baseball players are independent of where they are born.Identify the test statistic.(Round to three decimal places as needed.)Identify the P-value.(Round to three decimal places as needed.) State the final conclusion that addresses the original claim.НоThere isV evidence to warrant rejection of the claim that months of births of baseball players are independent of whether they are born in America.

Formula Used: χ2 = ∑O-E2E Expected value = Row total × Column totalN Degree of freedom = (Row-1) × (Column-1) Solution: Foreign born Expected value Born in America Expected value Total Jan 101 486×10345550 = 90.545 385 486×45165550 = 395.455 486 Feb 81 413×10345550 = 76.944 332 413×45165550 = 336.0555 413 March 86 451×10345550 = 84.024 365 451×45165550 = 366.976 451 April 83 427×10345550 = 79.553 344 427×45165550 = 347.447 427 May 95 434×10345550 = 80.857 339 434×45165550 = 353.143 434 June 83 399×10345550 = 74.336 316 399×45165550 = 324.664 399 july 59 374×10345550 = 69.679 315 374×45165550 = 304.321 374 August 91 594×10345550 = 110.666 503 594×45165550 = 483.334 594 September 70 489×10345550 = 91.104 419 489×45165550 = 397.896 489 October 99 532×10345550 = 99.115 433 532×45165550 = 432.885 532 November 104 501×10345550 = 93.339 397 501×45165550 = 407.660 501 December 82 450×10345550 = 83.838 368 450×45165550 = 366.1622 450 Total 1034 4516 5550O E (O-E) (O-E)2 O-E2E 101 90.545 10.455 109.307 1.207212 81 76.944 4.056 16.45114 0.213807 86 84.024 1.976 3.904576 0.04647 83 79.553 3.447 11.88181 0.149357 95 80.857 14.143 200.0244 2.473805 83 74.336 8.664 75.0649 1.009805 59 69.679 -10.679 114.041 1.636663 91 110.666 -19.666 386.7516 3.494764 70 91.104 -21.104 445.3788 4.888686 99 99.115 -0.115 0.013225 0.000133 104 93.339 10.661 113.6569 1.217679 82 83.838 -1.838 3.378244 0.040295 385 395.455 -10.455 109.307 0.276408 332 336.0555 -4.0555 16.44708 0.048942 365 366.976 -1.976 3.904576 0.01064 344 347.447 -3.447 11.88181 0.034197 339 353.143 -14.143 200.0244 0.566412 316 324.664 -8.664 75.0649 0.231208 315 304.321 10.679 114.041 0.374739 503 483.334 19.666 386.7516 0.800175 419 397.896 21.104 445.3788 1.119335 433 432.885 0.115 0.013225 3.06E-05 397 407.66 -10.66 113.6356 0.278751 368 366.1622 1.8378 3.377509 0.009224 ∑O-E2E=20.129Null hypothesis: H0 : Months of births of baes ball players are independent of where they are born. Alternative hypothesis: H1 : Months of births of base ball players are dependent of where they are born. Test-statistic χ2 = ∑O-E2E χ2 = 20.129 Degree of freedom = (Row-1) × (Column-1) = (2-1)×(12-1) = 11 For p-value: In MS Excel =CHISQ.DIST.RT(Test-statistic, df) p-value = 0.0436 {Rounded to 3 decimal places} Significance level α = 0.01 0.0436 > 0.01 Since, p-value is greater than significance level, we fail to reject the null hypothesis. Conclusion: There is not sufficient evidence to warrant rejection of the claim that months of births of base ball players are independent of whether they are born in America.Answer: Null hypothesis: H0 : Months of births of baes ball players are independent of where they are born. Alternative hypothesis: H1 : Months of births of base ball players are dependent of where they are born. Test-statistic χ2 = 20.129 p-value = 0.0436 Conclusion: There is not sufficient evidence to warrant rejection of the claim that months of births of base ball players are independent of whether they are born in America.