An atomic absorption method for the determination of the amount of iron present in used jet engine oil was found from pooling 30 triplicate analyses to have a standard deviation s = 3.1 µg Fe/mL. If s is a good estimate of o, calculate the 95 and 99% confidence intervals for the result 21.7 μg Fe/mL if it was based on the following criteria. (a) a single analysis 95% confidence interval = 21.7 + 99% confidence interval = 21.7 + (b) the mean of two analyses 95% confidence interval= 21.7 + 99% confidence interval= 21.7 + (c) the mean of six analyses 95% confidence interval= 21.7 + 99% confidence interval= 21.7 ± μg Fe/mL μg Fe/mL μg Fe/mL μg Fe/mL μg Fe/mL μg Fe/mL
An atomic absorption method for the determination of the amount of iron present in used jet engine oil was found from pooling 30 triplicate analyses to have a standard deviation s = 3.1 µg Fe/mL. If s is a good estimate of o, calculate the 95 and 99% confidence intervals for the result 21.7 μg Fe/mL if it was based on the following criteria. (a) a single analysis 95% confidence interval = 21.7 + 99% confidence interval = 21.7 + (b) the mean of two analyses 95% confidence interval= 21.7 + 99% confidence interval= 21.7 + (c) the mean of six analyses 95% confidence interval= 21.7 + 99% confidence interval= 21.7 ± μg Fe/mL μg Fe/mL μg Fe/mL μg Fe/mL μg Fe/mL μg Fe/mL
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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Transcribed Image Text:An atomic absorption method for the determination of the amount of iron present in used jet engine oil was found from pooling
30 triplicate analyses to have a standard deviation s = 3.1 µg Fe/mL. If s is a good estimate of o, calculate the 95 and 99%
confidence intervals for the result 21.7 µg Fe/mL if it was based on the following criteria.
(a) a single analysis
95% confidence interval= 21.7 +
99% confidence interval = 21.7 +
(b) the mean of two analyses
95% confidence interval = 21.7 +
99% confidence interval=
(c) the mean of six analyses
21.7 ±
95% confidence interval = 21.7 +
99% confidence interval= 21.7 +
μg Fe/mL
μg Fe/mL
μg Fe/mL
μg Fe/mL
μg Fe/mL
μg Fe/mL
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