An analytical chemist weighs out 0.252 g of an unknown diprotic acid into a 250 ml. volumetric flask and dilutes to the mark with distilled water. He then titrates this solution with 0.0500M NaOH solution. When the titration reaches the equivalence point, the chemist finds he has added 60.7 ml. of NaOH solution. Calculate the molar mass of the unknown acid. Round your answer to 3 significant digits.

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Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
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Chapter1: Chemical Foundations
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An analytical chemist weighs out 0.252 g of an unknown diprotic acid into a 250 ml. volumetric flask and dilutes to the mark with distilled water. He
then titrates this solution with 0.0500M NaOH solution. When the titration reaches the equivalence point, the chemist finds he has added 60.7 ml.
of NaOH solution.
Calculate the molar mass of the unknown acid. Round your answer to 3 significant digits.
Transcribed Image Text:An analytical chemist weighs out 0.252 g of an unknown diprotic acid into a 250 ml. volumetric flask and dilutes to the mark with distilled water. He then titrates this solution with 0.0500M NaOH solution. When the titration reaches the equivalence point, the chemist finds he has added 60.7 ml. of NaOH solution. Calculate the molar mass of the unknown acid. Round your answer to 3 significant digits.
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