An analytical chemist is titrating 139.4 mL of a 0.7600M solution of isopropylamine ((CH3)₂CHNH₂) with a 0.2500M solution of HNO3. The p K of isopropylamine is 3.33. Calculate the pH of the base solution after the chemist has added 308.2 mL of the HNO3 solution to it. Note for advanced students: you may assume the final volume equals the initial volume of the solution plus the volume of HNO3 solution added. Round your answer to 2 decimal places. pH = 0 X olo 18 Ar

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An analytical chemist is titrating 139.4 mL of a 0.7600M solution of isopropylamine ((CH3)2CHNH₂) with a 0.2500M
solution of HNO3. The p K of isopropylamine is 3.33. Calculate the pH of the base solution after the chemist has added
308.2 mL of the HNO3 solution to it.
?
Note for advanced students: you may assume the final volume equals the initial volume of the solution plus the volume of
HNO3 solution added.
Round your answer to 2 decimal places.
pH
=
0
X
Ś
000
18
Ar
Transcribed Image Text:An analytical chemist is titrating 139.4 mL of a 0.7600M solution of isopropylamine ((CH3)2CHNH₂) with a 0.2500M solution of HNO3. The p K of isopropylamine is 3.33. Calculate the pH of the base solution after the chemist has added 308.2 mL of the HNO3 solution to it. ? Note for advanced students: you may assume the final volume equals the initial volume of the solution plus the volume of HNO3 solution added. Round your answer to 2 decimal places. pH = 0 X Ś 000 18 Ar
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