### Titration of Benzoic Acid**Problem Statement**A chemist titrates 220.0 mL of a 0.4703 M benzoic acid (\[HC_6H_5CO_2\]) solution with 0.0972 M NaOH solution at 25 °C. Calculate the pH at equivalence.The \( pK_a \) of benzoic acid is 4.20.Round your answer to 2 decimal places.**Note for Advanced Students:**You may assume the total volume of the solution equals the initial volume plus the volume of NaOH solution added.---This problem requires understanding the concepts of acid-base titration, particularly at the equivalence point where the amount of acid is stoichiometrically equal to the amount of base added. At equivalence, for a weak acid titrated with a strong base, the solution typically contains the conjugate base of the weak acid, which will hydrolyze slightly in water.To solve, follow these steps:1. **Determine the moles of benzoic acid and NaOH:** - Moles of benzoic acid \( (\text{mol} HA) \): \[ \text{mol HA} = 0.4703 \, M \times 0.2200 \, L = 0.103466 \, \text{mol} \] - Moles of NaOH needed: \[ \text{mol NaOH} = \text{mol HA} = 0.103466 \, \text{mol} \]2. **Volume of NaOH solution needed:** - Volume \( (V_{\text{NaOH}}) \): \[ V_{\text{NaOH}} = \frac{\text{mol NaOH}}{0.0972 \, M} = \frac{0.103466 \, \text{mol}}{0.0972 \, M} = 1.0649 \, L \] Considering significant figures—1.065 L.3. **Total Volume at Equivalence:** - Total volume \( V_{\text{total}} \): \[ V_{\text{total}} = 0.2200 \, L + 1.065 \, L = 1.285 \, L \]4. **Concentration of the conjugate

We have to calculate the pH at equivalence point

A chemist titrates 220.0 mL of a 0.4703M benzoic acid (HCH₂CO₂) solution with 0.0972M NaOH solution at 25 °C. Calculate the pH at equivalence. The pK of benzoic acid is 4.20. Round your answer to 2 decimal places. Note for advanced students: you may assume the total volume of the solution equals the initial volume plus the volume of NaOH solution added.

A chemist titrates 220.0 mL of a 0.4703M benzoic acid (HCH₂CO₂) solution with 0.0972M NaOH solution at 25 °C. Calculate the pH at equivalence. The pK of benzoic acid is 4.20. Round your answer to 2 decimal places. Note for advanced students: you may assume the total volume of the solution equals the initial volume plus the volume of NaOH solution added.

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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