A chemist titrates 120.0 mL of a 0.2065 M benzoic acid (HC HCO₂) solution with 0.6703 M NaOH solution at 25 °C. Calculate the pH at equivalence. The PK of benzoic acid is 4.20. Round your answer to 2 decimal places. Note for advanced students: you may assume the total volume of the solution equals the initial volume plus the volume of NaOH solution added.

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Chapter16: Acid-base Equilibria
Section: Chapter Questions
Problem 16.149QP: A solution of weak base is titrated to the equivalence point with a strong acid. Which one of the...
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A chemist titrates 120.0 mL of a 0.2065 M benzoic acid (HC HCO₂) solution with 0.6703 M NaOH solution at 25 °C. Calculate the pH at equivalence. The
pk of benzoic acid is 4.20.
a
Round your answer to 2 decimal places.
Note for advanced students: you may assume the total volume of the solution equals the initial volume plus the volume of NaOH solution added.
pH =
×
Ś
Transcribed Image Text:A chemist titrates 120.0 mL of a 0.2065 M benzoic acid (HC HCO₂) solution with 0.6703 M NaOH solution at 25 °C. Calculate the pH at equivalence. The pk of benzoic acid is 4.20. a Round your answer to 2 decimal places. Note for advanced students: you may assume the total volume of the solution equals the initial volume plus the volume of NaOH solution added. pH = × Ś
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