### Titration Problem - Calculating pHAn analytical chemist is titrating 238.1 mL of a 0.5500 M solution of propionic acid (\(HC_2H_5CO_2\)) with a 0.8000 M solution of KOH. The \(pK_a\) of propionic acid is 4.89. Calculate the pH of the acid solution after the chemist has added 119.8 mL of the KOH solution to it.**Note for advanced students:** You may assume the final volume equals the initial volume of the solution plus the volume of KOH solution added.**Instructions:** Round your answer to 2 decimal places and enter it in the provided box.**pH Calculation Box:**\[ \text{pH} = \boxed{} \]### Explanation:In this problem, we are dealing with a titration of a weak acid (propionic acid) with a strong base (KOH). The objective is to calculate the pH after the addition of a specific volume of KOH.### Detailed Solution Approach:1. **Determine the moles of propionic acid and KOH:** - Moles of propionic acid (\(HC_2H_5CO_2\)): \( \text{Molarity} \times \text{Volume} = 0.5500 \, M \times 0.2381 \, L = 0.130955 \, \text{moles} \) - Moles of KOH: \( \text{Molarity} \times \text{Volume} = 0.8000 \, M \times 0.1198 \, L = 0.09584 \, \text{moles} \)2. **Calculate the remaining moles of \(HC_2H_5CO_2\) and produced moles of \(HC_2H_5CO_2^- \):** - Stoichiometry: \(HC_2H_5CO_2H + OH^- \rightarrow HC_2H_5CO_2^- + H_2O \) - Moles of \(HC_2H_5CO_2H\) after reaction: \(0.130955 - 0.09584 = 0.035115 \, \text{moles}\

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An analytical chemist is titrating 238.1 mL of a 0.5500M solution of propionic acid (HC₂H₂CO₂) with a 0.8000M solution of KOH. The p K of propionic acid is 4.89. Calculate the pH of the acid solution after the chemist has added 119.8 mL of the KOH solution to it. Note for advanced students: you may assume the final volume equals the initial volume of the solution plus the volume of KOH solution added. Round your answer to 2 decimal places. pH = X

An analytical chemist is titrating 238.1 mL of a 0.5500M solution of propionic acid (HC₂H₂CO₂) with a 0.8000M solution of KOH. The p K of propionic acid is 4.89. Calculate the pH of the acid solution after the chemist has added 119.8 mL of the KOH solution to it. Note for advanced students: you may assume the final volume equals the initial volume of the solution plus the volume of KOH solution added. Round your answer to 2 decimal places. pH = X

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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