an algorithm for finding the most frequently occurring value in an array of numbers. #include using namespace std;
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an
an array of numbers.
#include<iostream>
using namespace std;
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- void Q1_1() { } const int SIZE = 22; char value[] = ('c', 'e', 'E', 'p', '1', 'u', 's', 'P', 'L', ‘U', 'S'}; //ASCII code of A to Z is 65 to 90 cout<I need the pseudocode or flowchart for the following code: #include <stdio.h>#include <stdlib.h>#include <string.h>#define array_Length 5#define BUFSIZE 40//Calculate the average int getmean (int *arr, int length) {int sum = 0;for (int i=0; i<length; i++){sum += arr[i];}//end for loopreturn sum/length;}//Output the Maximum int find_Maximum(int *arr,int length) {int max=0;for(int i=1;i<length;++i)if (arr[i]>arr[max])max=i;return arr[max];}//end for loopint main() {//Intialize and Declare Variables int values[array_Length] = {0};char buffer[BUFSIZE];int index = 0;int x = 0;while(x<5) {//Ask user to input integer printf ("Type a number:");x++;if (fgets(buffer, BUFSIZE, stdin) == NULL)break;//Save new int in the array values[index] = atoi(buffer);//Move the index to the next element, wrap around if needed index = (index + 1) % array_Length;//Display the array, maximum number and the average of its valueprintf("[");for (int i= 0; i < array_Length; i++)…#include<stdio.h>#include<string.h>struct info{char names[100];int age;float wage;};int main(int argc, char* argv[]) {int line_count = 0;int index, i;struct info hr[10];if (argc != 2)printf("Invalid user_input!\n");else {FILE* contents = fopen (argv[1], "r");struct info in;if (contents != NULL) {printf("File has been opened successfully.\n\n");while (fscanf(contents, "%s %d %f\n",hr[line_count].names, &hr[line_count].age, &hr[line_count].wage) != EOF) {printf("%s %d %f\n", hr[line_count].names, hr[line_count].age, hr[line_count].wage);line_count++;}printf("\nTotal number of lines in document are: %d\n\n", line_count);fclose(contents);printf("Please enter a name: ");char user_input[100];fgets(user_input, 30, stdin);user_input[strlen(user_input)-1] = '\0';index = -1;for(i = 0; i < line_count; i++){if(strcmp(hr[i].names, user_input) == 0){index = i;break;}}if(index == -1)printf("Name %s not found\n", user_input);else{while(fread(&in, sizeof(struct info), 1,…C++ programhere is a and b part plz solve c part #include <iostream>#include <string.h>#include <stdlib.h>#include <sstream>#include <cmath>using namespace std; int main(){ /*Variable declarations*/int higestDegree,higestDegree1;int diffDegree,smallDegree;std::stringstream polynomial,addpolynomial;/*prompt for degree*/std::cout<<"Please enter higest degree of polynomial"<<std::endl;std::cin>>higestDegree; std::cout<<"Please Enter highest degree of 2nd polynomial"<<std::endl;std::cin>>higestDegree1;int *cofficient=new int[higestDegree+1];//cofficient array creation for 1st polynomailint *cofficient1=new int[higestDegree1+1];//cofficient array creation for 2st polynomail /*taking cofficient for 1st polynomial*/std::cout<<"Please enter cofficient of each term from higest degree to lowest for 1st polynomial"<<std::endl;for(int i=0;i<=higestDegree;i++){std::cin>>cofficient[i];}/*taking cofficient for 2st…initial c++ file/starter code: #include <vector>#include <iostream>#include <algorithm> using namespace std; // The puzzle will always have exactly 20 columnsconst int numCols = 20; // Searches the entire puzzle, but may use helper functions to implement logicvoid searchPuzzle(const char puzzle[][numCols], const string wordBank[],vector <string> &discovered, int numRows, int numWords); // Printer function that outputs a vectorvoid printVector(const vector <string> &v);// Example of one potential helper function.// bool searchPuzzleToTheRight(const char puzzle[][numCols], const string &word,// int rowStart, int colStart) int main(){int numRows, numWords; // grab the array row dimension and amount of wordscin >> numRows >> numWords;// declare a 2D arraychar puzzle[numRows][numCols];// TODO: fill the 2D array via input// read the puzzle in from the input file using cin // create a 1D array for wodsstring wordBank[numWords];// TODO:…The elements displayed by the following section code For(m=1;m<=5;m++) cout <<a[m] <<"" ;#include <iostream> using namespace std; int rectArea (int len, int wid) { return len * wid; } int main () { int length, width; cin >> length >> width; cout << "The area of a " << length << " by " << width << " rectangle is " << /*add code to call the reacArea function */ << "." << endl; return 0; }#include <iostream> using namespace std; int main(){ int a[100],n,i,item,loc=0; cout<<"Enter number of elements: "; cin>>n; cout<<"\nEnter numbers:\n"; for(i=1;i<=n;i++) { cin>>a[i]; } cout<<"\nEnter number to search:"; cin>>item; for(i=1;i<=n;i++) { if(item==a[i]) { loc=i; break; } } if(loc>0) { cout<<loc<<" is the location of item"; } else cout<<"\nno. not found";} Q: edit the code that shows after how many number of iteration searched value is foundPlease fix this code for me, I'm stuck . #include<iostream>#include <iomanip>using namespace std;// the main bodyint main(){std::string item[10],name;int n;float price[10],ST_VAT[10],tax[10],total=0.0,Net;cout<<"Enter the number of items that should be atleast 5 : ";cin>>n;cout<<"Enter the customer's name ";cin>>name;for(int i=1;i<=n;i++){ std::cout<<"\nEnter the item "<<i<<" name , cost, sales tax and VAT :";cin>>name>>price[i]>>ST_VAT[i];tax[i]=price[i]+ST_VAT[i];total=total+tax[i];}Net=total-0.05*total;cout<<swet(5)<<"Food Stuff Grocery Shop"<<endl;cout<<"Customer Name"<<name<<endl;cout<<"ITEM"swet(8)<<"PRICE"<<swet(15)"Sales Tax+ VAT"<<swet(10)<<Sub-Total endl;cout<<SWET(8)<<"------------"<<swet(15)<<"--------------"<<swet(10)<<"----------"endl;for(int…C++ ARRAYC++ 2D ARRAY, Continue this codes and change the array to seat[6][6]. Include a loop that asks the user if he wants to try again or no. If the user enters the reserved seat again then display "this seat is taken already". Upon trying again, the reserved seat displayed as (X) must be displayed. My Code: #include <iostream> using namespace std; int main() { cout << "Bus Seats:\n"; cout << "* A B C D\n" << "1 * * * *\n" << "2 * * * *\n" << "3 * * * *\n" << "4 * * * *\n"; char seat[5][5]; int row, column; char col; cout << "Enter the row of your selected seat: "; cin >> row; cout << "Enter the column of your selected seat: "; cin >> col; for(int i=0; i<5; i++){ for(int j=0; j<5; j++){ if(i==0){ switch (j) { case 0: seat[i][j]='*'; break; case 1: seat[i][j]='A'; break; case 2: seat[i][j]='B'; break; case 3: seat[i][j]='C'; break; case 4: seat[i][j]='D'; break; } } else if (j==0) { switch(i) { case 1: seat[i][j]='1';…SEE MORE QUESTIONS
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