An air-conditioner which uses R-134a operates on the ideal vapor compression refrigeration cycle with a given compressor efficiency. --Given Values-- Evaporator Temperature: T1 (C) = 15 Condenser Temperature: T3 (C) = 32 Mass flow rate of refrigerant: mdot (kg/s) = 0.027 Compressor Efficiency: nc (%) = 77 a) Determine the specific enthalpy (kJ/kg) at the compressor inlet. Your Answer =255.6725 b) Determine the specific entropy (kJ/kg-K) at the compressor inlet Your Answer =0.912 c) Determine the specific enthalpy (kJ kg) at the compressor exit Your Answer =264.48 d) Determine the specific enthalpy (kJ/kg) at the condenser exit. Your Answer =94.39 e) Determine the specific enthalpy (kJ/kg) at the evaporator inlet. Your Answer =94.39 f) Determine the coefficient of performance for the system. Your Answer =1.45 g) Determine the cooling capacity (kW) of the system. Your Answer =4.35 h) Determine the power input (kW)to the compressor. Your Answer =3 ]Correct! Exact Answer= 255.67 +/- 1.0E-00 Correct! Exact Answer= 0.9120 +/- 3.7E-03 ] Incorrect. Correct! Exact Answer= 94.39 +/-5.3E-01 Correct! Exact Answer= 94.39 +/- 5.3E-01 | Incorrect. Correct! Exact Answer= 4.355 +/- 1.3E-02 Incorrect.

An air-conditioner which uses R-134a operates on the ideal vapor compression refrigeration cycle with a given compressor efficiency. --Given Values-- Evaporator Temperature: T1 (C) = 15 Condenser Temperature: T3 (C) = 32 Mass flow rate of refrigerant: mdot (kg/s) = 0.027 Compressor Efficiency: nc (%) = 77 a) Determine the specific enthalpy (kJ/kg) at the compressor inlet. Your Answer =255.6725 b) Determine the specific entropy (kJ/kg-K) at the compressor inlet Your Answer =0.912 c) Determine the specific enthalpy (kJ kg) at the compressor exit Your Answer =264.48 d) Determine the specific enthalpy (kJ/kg) at the condenser exit. Your Answer =94.39 e) Determine the specific enthalpy (kJ/kg) at the evaporator inlet. Your Answer =94.39 f) Determine the coefficient of performance for the system. Your Answer =1.45 g) Determine the cooling capacity (kW) of the system. Your Answer =4.35 h) Determine the power input (kW)to the compressor. Your Answer =3 ]Correct! Exact Answer= 255.67 +/- 1.0E-00 Correct! Exact Answer= 0.9120 +/- 3.7E-03 ] Incorrect. Correct! Exact Answer= 94.39 +/-5.3E-01 Correct! Exact Answer= 94.39 +/- 5.3E-01 | Incorrect. Correct! Exact Answer= 4.355 +/- 1.3E-02 Incorrect.

Elements Of Electromagnetics

7th Edition

ISBN:9780190698614

Author:Sadiku, Matthew N. O.

Publisher:Sadiku, Matthew N. O.

ChapterMA: Math Assessment

Section: Chapter Questions

Problem 1.1MA

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PART A ONLY ( USE IMAGE BELOW) In a standard ideal refrigeration cycle (Fig. 1), the refrigerant 134a enters adiabatically isolated expansion valve as a saturated liquid at a pressure P1 = 1 MPa and leaves the device at a pressure P2 = 100kPa. Then the refrigerant enters the evaporator, where it changes into the saturated vapor. Subsequently, the vapor is compressed in an isentropic compressor to the pressure 1MPa and condensed in the condenser back to the initial saturated-liquid state. PART A - Determine the heat qL absorbed by the refrigerant in the evaporator and the compressor work win (per 1 kg of the refrigerant).
Required information Refrigerant-134a enters the condenser of a steady-flow Carnot refrigerator as a saturated vapor at 65.0 psia, and it leaves with a quality of 0.05. The heat absorption from the refrigerated space takes place at a pressure of 30 psia. Determine the coefficient of performance. (Round the final answer to three decimal places.) The coefficient of performance is
The figure shows a two-stage, vapor-compression refrigeration system with two evaporators and a direct contact heat exchanger. Saturated vapor ammonia from evaporator 1 enters compressor 1 at 12 lbf/in² and exits the compressor at 46 lbf/in². Evaporator 2 operates at 46 lbf/in2, with saturated vapor exiting at state 8. The condenser pressure is 200 lbf/in2, and saturated liquid refrigerant exits the condenser. Each compressor stage has an isentropic efficiency of 80%. The refrigeration capacity of each evaporator is shown on the figure. Step 1 -5 Expansion A valve +6 -7 Evaporator Expansion valve Qout Condenser Compressor 2 Qin,2 = 10 tons 8 Evaporator Compressor Direct contact heat exchanger in,1 = 5 tons W₁₂
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Q2/ In simple refrigeration system uses R134a, the evaporator pressure is 0.25 MPa and the condenser pressure is 1. MPa. The evaporator load is 25 TR. Determine the required work to operate the compressor motor in (a) kW, (b) hp. What is the displacement volume of the compressor if the volumetric efficiency is 80%
42. Refrigerant-12 enters the condenser of a vapor-compression refrigera- tion system at 175 psia and 140°F and leaves as saturated liquid at 120°F. Mass flow rate of the refrigerant is 4.8 lbm/min. The heat is rejected to the surrounding air, which is at 90°F. Determine: (a) Heat rejection rate, Btu/hr. 22 (b) Separate the overall entropy changes per hour (Freon and sur- roundings). 23/
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The values of a vapor compression refrigeration cycle were given below. Calculate the values ofrefrigerant flow rate, refrigeration capacity, and the COP of the system.T1= Evaporator water outlet = 10 °CT2= Evaporator water inlet = 16 °CT3= Condenser water inlet = 16 °CT4= Condenser water outlet = 22°CCooling water flow rate = 1.5 L/minHeating water flow rate = 1.5 L/minEnthalpy of R134a in evaporator outlet = 305 kj/kg,Enthalpy of R134a in evaporator inlet =115 kj/kgEnthalpy of R134a in condenser inlet =327 kj/kg
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Below is an ideal cascade refrigeration system with High P = 800 kPa, Intermediate P = 360 kPa, and Low P = 140 kPa.If the lower cycle transfers 69kW of energy to the upper cycle, What is the mass flow rate of R-134A (in kg/s) in the upper cycle? a.0.4014 b.0.3892 c.0.3554 d.0.4357
Please help!!!! Refrigerant 22 enters the compressor of an ideal vapor-compression refrigeration system as saturated vapor at -30°C with a volumetric flow rate of 10 m3/min. The refrigerant leaves the condenser at 19°C, 9 bar. Determine: (a) the magnitude of the compressor power, in kW. (b) the refrigerating capacity, in tons. (c) the coefficient of performance. (d) the rate of entropy production for the cycle, in kW/K. Answer for part (a): 52 kW Answer for part (b): 59 tons Answer for part (c): 3.98 Please answer part also d! That's the part I also need. Thank you!