An air-conditioner which uses R-134a operates on the ideal vapor compression refrigeration cycle with a given compressor efficiency. --Given Values-- Evaporator Temperature: T1 (C) = 15 Condenser Temperature: T3 (C) = 32 Mass flow rate of refrigerant: mdot (kg/s) = 0.027 Compressor Efficiency: nc (%) = 77 a) Determine the specific enthalpy (kJ/kg) at the compressor inlet. Your Answer =255.6725 b) Determine the specific entropy (kJ/kg-K) at the compressor inlet Your Answer =0.912 c) Determine the specific enthalpy (kJ kg) at the compressor exit Your Answer =264.48 d) Determine the specific enthalpy (kJ/kg) at the condenser exit. Your Answer =94.39 e) Determine the specific enthalpy (kJ/kg) at the evaporator inlet. Your Answer =94.39 f) Determine the coefficient of performance for the system. Your Answer =1.45 g) Determine the cooling capacity (kW) of the system. Your Answer =4.35 h) Determine the power input (kW)to the compressor. Your Answer =3 ]Correct! Exact Answer= 255.67 +/- 1.0E-00 Correct! Exact Answer= 0.9120 +/- 3.7E-03 ] Incorrect. Correct! Exact Answer= 94.39 +/-5.3E-01 Correct! Exact Answer= 94.39 +/- 5.3E-01 | Incorrect. Correct! Exact Answer= 4.355 +/- 1.3E-02 Incorrect.
An air-conditioner which uses R-134a operates on the ideal vapor compression refrigeration cycle with a given compressor efficiency. --Given Values-- Evaporator Temperature: T1 (C) = 15 Condenser Temperature: T3 (C) = 32 Mass flow rate of refrigerant: mdot (kg/s) = 0.027 Compressor Efficiency: nc (%) = 77 a) Determine the specific enthalpy (kJ/kg) at the compressor inlet. Your Answer =255.6725 b) Determine the specific entropy (kJ/kg-K) at the compressor inlet Your Answer =0.912 c) Determine the specific enthalpy (kJ kg) at the compressor exit Your Answer =264.48 d) Determine the specific enthalpy (kJ/kg) at the condenser exit. Your Answer =94.39 e) Determine the specific enthalpy (kJ/kg) at the evaporator inlet. Your Answer =94.39 f) Determine the coefficient of performance for the system. Your Answer =1.45 g) Determine the cooling capacity (kW) of the system. Your Answer =4.35 h) Determine the power input (kW)to the compressor. Your Answer =3 ]Correct! Exact Answer= 255.67 +/- 1.0E-00 Correct! Exact Answer= 0.9120 +/- 3.7E-03 ] Incorrect. Correct! Exact Answer= 94.39 +/-5.3E-01 Correct! Exact Answer= 94.39 +/- 5.3E-01 | Incorrect. Correct! Exact Answer= 4.355 +/- 1.3E-02 Incorrect.
Elements Of Electromagnetics
7th Edition
ISBN:9780190698614
Author:Sadiku, Matthew N. O.
Publisher:Sadiku, Matthew N. O.
ChapterMA: Math Assessment
Section: Chapter Questions
Problem 1.1MA
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![An air-conditioner which uses R-134a operates on the ideal vapor compression refrigeration cycle with a given compressor efficiency.
--Given Values--
Evaporator Temperature: T1 (C) = 15
Condenser Temperature: T3 (C) = 32
Mass flow rate of refrigerant: mdot (kg/s) = 0.027
Compressor Efficiency: nc (%) = 77
a) Determine the specific enthalpy (kJ kg) at the compressor inlet.
Your Answer =255.6725
b) Determine the specific entropy (kJ kg-K) at the compressor inlet
Your Answer =0.912
c) Determine the specific enthalpy (kJ/kg) at the compressor exit
Your Answer =264.48
d) Determine the specific enthalpy (kJ/kg) at the condenser exit.
Your Answer =94.39
e) Determine the specific enthalpy (kJ/kg) at the evaporator inlet.
Your Answer =94.39
f) Determine the coefficient of performance for the system.
Your Answer = 1.45
g) Determine the cooling capacity (kW) of the system.
Your Answer =4.35
h) Determine the power input (kW)to the compressor.
Your Answer =3
Correct! Exact Answer= 255.67 +/- 1.0E+00
Correct! Exact Answer= 0.9120 +/- 3.7E-03
| Incorrect.
Correct! Exact Answer= 94.39 +/- 5.3E-01
Correct! Exact Answer= 94.39 +/- 5.3E-01
Incorrect.
Correct! Exact Answer= 4.355 +/- 1.3E-02
Incorrect.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F7a9d2f52-c349-4ef7-9ba8-170c32c01abf%2Fae797935-4059-498b-bb15-993ecdf2f8c0%2F4f3dznh_processed.jpeg&w=3840&q=75)
Transcribed Image Text:An air-conditioner which uses R-134a operates on the ideal vapor compression refrigeration cycle with a given compressor efficiency.
--Given Values--
Evaporator Temperature: T1 (C) = 15
Condenser Temperature: T3 (C) = 32
Mass flow rate of refrigerant: mdot (kg/s) = 0.027
Compressor Efficiency: nc (%) = 77
a) Determine the specific enthalpy (kJ kg) at the compressor inlet.
Your Answer =255.6725
b) Determine the specific entropy (kJ kg-K) at the compressor inlet
Your Answer =0.912
c) Determine the specific enthalpy (kJ/kg) at the compressor exit
Your Answer =264.48
d) Determine the specific enthalpy (kJ/kg) at the condenser exit.
Your Answer =94.39
e) Determine the specific enthalpy (kJ/kg) at the evaporator inlet.
Your Answer =94.39
f) Determine the coefficient of performance for the system.
Your Answer = 1.45
g) Determine the cooling capacity (kW) of the system.
Your Answer =4.35
h) Determine the power input (kW)to the compressor.
Your Answer =3
Correct! Exact Answer= 255.67 +/- 1.0E+00
Correct! Exact Answer= 0.9120 +/- 3.7E-03
| Incorrect.
Correct! Exact Answer= 94.39 +/- 5.3E-01
Correct! Exact Answer= 94.39 +/- 5.3E-01
Incorrect.
Correct! Exact Answer= 4.355 +/- 1.3E-02
Incorrect.
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