GUIDED PROBLEMAn 8 m long steel column is pinned at the top and fixed at the bottom. The column is providedwith lateral support at mid-height about the weak axis.The properties of the column section are as follows:178.1 x 10 mmly = 18.8 x 10 mm*A=8129 mm²fy=400 MPaWhat is the critical effective slenderness ratio?What is the Euler critical load?What is the Euler critical stress?a) Determine the effective lengths:a. About the x-axis: It is pinned at the top and fixed at the bottom.k=_L =_Effective length:b. About the y-axis: The lateral support at the mid-height will take effect. There willbe two segments. Both have lengths of:One of the segments have the pinned support and the lateral support. It will be treated aspinned ends. Thus, k=. The unbraced length is L=The effective length is:kL=The other segment have the fixed support and the lateral support. It will be treated as fixed-pinned column. Thus, k =. The unbraced length is L=The effective length is:kl=From the two effective lengths, choose the larger value (since it is more critical in slenderness.Thus, the effective length for the y-axis is:Effective length: KL=kL=b) Euler Critical Load:Using E= 200 GPa for steel, the critical load based on the slenderness in the x-axis is:Now, that of the slendemess in the y-axis,c) Euler Critical Stress:Using stress = Force / Area,Pcy=n²ElxPax=L²₂²Ely=L²Choose the smaller load: Perit =This is now the maximum load that the column cancarry without considering buckling. (The load where the column will start to buckle)Pcrit ==

Moment of inertia about x axis, Moment of inertia about x axis, Area of section, Yield strength, To…

An 8 m long steel column is pinned at the top and fixed at the bottom. The column is provided with lateral support at mid-height about the weak axis. The properties of the column section are as follows: 1,= 178.1 x 10 mm ly = 18.8 x 10 mm A=8129 mm² fy=400 MPa What is the critical effective slenderness ratio? What is the Euler critical load? What is the Euler critical stress?

An 8 m long steel column is pinned at the top and fixed at the bottom. The column is provided with lateral support at mid-height about the weak axis. The properties of the column section are as follows: 1,= 178.1 x 10 mm ly = 18.8 x 10 mm A=8129 mm² fy=400 MPa What is the critical effective slenderness ratio? What is the Euler critical load? What is the Euler critical stress?

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

See similar textbooks

Similar questions

A steel rod of 20mm is enclosed centrally in a hollow copper tube of external diameter 40mm and internal diameter of 35mm the composite bar is then subjected to an axial pull of 50KN.If the length of each bar is equal to 200mm,determine 1.The stress in the rod and the tube 2.Load carried by each bar Take E for steel=200KN/mm2 and copper =100KN/mm2
1. The assembly has the diameters and material makeup indicated. If it fits securely between its fixed supports when the temperature is T; = 70°F, determine the average normal stress in each material when the temperature reaches T2 = 130°F. 304 Stainless steel - 2014-T6 Aluminum -C 86100 Bronze A 12 in. 8 in. D C 4 in. -4 ft- 6 ft- 3 ft
Solve this problem using stiffness Method and draw SFD and BMD P=95 STRUCTURE-2
Please answer the question correctly and pleaase put the answer on the paper. Thank you Note: The tolerance is ± 1 in the third significant digit. Put the exact answer
Q/ Find the Maximum stresses in Steel and Aluminum. Est= 210G pa and E al%3D 70 G pa ? W= 15 Kn.M 120mm 5m Al steel 60mm 140 mm
PLEASe answer this question. Thank you
3. Determine the stress in each of the two vertical rods if the temperature rises 50 °C after the load P=75 KN is applied. Neglect the deformation and mass of the horizontal bar AB. Use Ea = 75 GPa, as=23.0 um/m-°C, Aa = 850 mm2 Es = 210 GPa, as = 11.9 um/m-°C and As = 650 mm² . %3D %3D Steel Aluminum 3m 2.5m 3 m 3 m 3 m 75 KN
A rectangular steel block is 3.2 inches long in the x-direction, 2.9 inches long in the y-direction, and 4.5 inches long in the z-direction. The block is subjected to a tri-axial loading of three uniformly distributed forces as follows: 48 kips tension in the x-direction, 65 kips compression in the y-direction, and 54 kips tension in the z-direction. If Poisson's ratio is 0.30 and E = 29 x 106 psi, find the uniformly distributed load that must be added in the x-direction to produced no deformation in the z-direction. Your final answer should include two decimal places
A rectangular steel block is 3.0 inches long in the x-direction, 3.0 inches long in the y-direction, and 4.5 inches long in the z-direction. The block is subjected to a tri-axial loading of three uniformly distributed forces as follows: 50 kips tension in the x-direction, 60 kips compression in the y-direction, and 54 kips tension in the z-direction. If Poisson's ratio is 0.30 and E = 29 x 106 psi, find the uniformly distributed load that must be added in the x-direction to produced no deformation in the z-direction. Your final answer should include two decimal places
1. Shown is a composite plate joined together by rivets. The components consist of two tension bar plates that is % X 4 inch and riveted together by two splice plates which is 0.8 X 6 inch. Each rivet has a diameter of 25.4 mm. Considering that the allowable stress for the tension bar plates and splice plates is o=20.0 ksi, the allowable shear stress for the rivets is o=25.0 ksi and the allowable bearing stress on the rivets and splice plates is o=25.0 ksi. What will be the maximum permissible load P such that none of the allowable stresses will be exceeded? Splice Plates a-0.75 in Bar Lc =0.80 in. Bar P d = 1.0 in. b=4.0 in. Rivets 'e = 6.0 in.
Consider the column section below. It has eight #9 bars. The material properties are as follows: fr =4,000 psi, f, = 60 ksi, and E. = 29,000 ksi . The cross-sectional area of a #9 bar is 1.0 in.2². 8- #9 0000 2.5" 44 Axis of bending 20" 15" 2.5" 20" P M If the tensile strain in the reinforcing bars cannot be lower than 0.007 when its nominal moment capacity is reached, using the principles of mechanics to determine the maximum axial load n P, that can be carried by the column. Determine the corresponding nominal moment capacity Mn. (you cannot use any design aid) (Ans: Pn = 246 kips, Mn = 460 kip-ft)
42 KN the cross-sectional area of each member is 600 mm² Determine the stress in member EF. Answer in MPa rounded-off to 2 decimal places AddSNUIF ana. 2m A Last saved 4:09:09 PM 1455 ET 2 m Next > Last >