Answered: Ammonium carbamate, (NH4)(OCONH2) (FW…

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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Ammonium carbamate, (NH4)(OCONH2) (FW 78.071), is unstable, decomposing into ammonia (FW 17.03) and carbon dioxide (FW 44.01).

(NH4)(OCONH2) (s) -> 2 NH3 (g) + CO2 (g)

A 5.00 g portion of solid ammonium carbamate was placed in a 5.00-L container. The air was removed from the sealed container and the reaction shown above was allowed to reach equilibrium at 25 oC.
Once equilibrium was reached, the pressure in the container was found to be 0.27 atm.

Calculate KP for this reaction at 25 oC.

Expert Solution

Step 1

Recall the given reaction

$(N H_{4}) (O C O N H_{2}) (s) \to 2 N H_{3} (g) + C O_{2} (g)$

Write expression of K_p

$K_{p} = {(P_{N H_{3}})}^{2} \times (P_{C O_{2}}) (A s P_{(N H_{4}) (O C O N H_{2}) (s)} = 1)$

A 5.00 g of solid ammonium carbamate was placed in 5.00 L container

When the system reaches equilibrium total pressure of the container is 0.27 atm

Now in equilibrium only products ammonia and carbon dioxide remain in gaseous state in the ratio of 2:1

So Partial pressure of NH₃

$P_{N H_{3}} = \frac{2}{3} \times (0.27) a t m P_{N H_{3}} = 0.18 a t m$

and partial pressure of CO₂

$P_{C O_{2}} = \frac{1}{3} (0.27) a t m P_{C O_{2}} = 0.09 a t m$

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