(1)(2)]A certain species of trout requires dissolved oxygen of 7.5 mg/L. Would it be wise to release thetrout in a mountain stream at an altitude with a Po2 = 0.17 atm. (KH (02) = 1.3x10-³ mol/Latm).Calculate the mole fraction for the following:14.5 g of HNO3 in 150 g of H₂O.(b)moles of Solutekg SolventX(a)H=1.01N = 14.00- 50 mm= 63.01 g/mol03=16.0x3Imol14.6g HNO363.01g149150 g1000g = 0.15 kg6.00 M HCI. (notice, concentration is an extensive property. You can assumeany volume!)0.23 mol HNO30.16 kg H2O1.53= 0.23 mol HNO3

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(1) release the A certain species of trout requires dissolved oxygen of 7.5 mg/L. Would it be wise t trout in a mountain stream at an altitude with a Poz = 0.17 atm. (KH (02) = 1.3x10-³ mol/Latm).

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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Solutions

Solutions can be considered as homogeneous mixtures which contain two or more than two chemical substances. The chemical substance which is the greater part is defined as solvent. And the chemical substance that is dissolved in a solvent is referred to as solute. Solution chemistry plays an important role in chemistry since it supports many commercial applications of solutions.

Question

(1)
(2)
]
A certain species of trout requires dissolved oxygen of 7.5 mg/L. Would it be wise to release the
trout in a mountain stream at an altitude with a Po2 = 0.17 atm. (KH (02) = 1.3x10-³ mol/Latm).
Calculate the mole fraction for the following:
14.5 g of HNO3 in 150 g of H₂O.
(b)
moles of Solute
kg Solvent
X
(a)
H=1.01
N = 14.00- 50 mm= 63.01 g/mol
03=16.0x3
Imol
14.6g HNO3
63.01g
149
150 g
1000g = 0.15 kg
6.00 M HCI. (notice, concentration is an extensive property. You can assume
any volume!)
0.23 mol HNO3
0.16 kg H2O
1.53
= 0.23 mol HNO3

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