Ammonia (NH₂) gas and oxygen (0₂) gas react to form nitrogen (N₂) gas and water (H₂O) vapor. Suppose you have 3.0 mol of NH3 and 11.0 mol of O₂ in a reactor. Suppose as much as possible of the NH3 reacts. How much will be left? Round your answer to the nearest 0.1 mol. mol X S

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Solving moles-to-moles limiting reactant problems
Ammonia (NH₂)
a reactor.
mol
gas and oxygen (O₂) gas react to form nitrogen (N₂)
Explanation
gas and water
Suppose as much as possible of the NH3 reacts. How much will be left? Round your answer to the nearest 0.1 mol.
Check
(H₂O)
vapor. Suppose you have 3.0 mol of NH3 and 11.0 mol of O₂ in
On
Ar
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Transcribed Image Text:Solving moles-to-moles limiting reactant problems Ammonia (NH₂) a reactor. mol gas and oxygen (O₂) gas react to form nitrogen (N₂) Explanation gas and water Suppose as much as possible of the NH3 reacts. How much will be left? Round your answer to the nearest 0.1 mol. Check (H₂O) vapor. Suppose you have 3.0 mol of NH3 and 11.0 mol of O₂ in On Ar 2020 McGraw Hill LLC. All Rights Reserved. Terms of Use | Privacy Center | Accessibility
Expert Solution
Step 1: Balanced chemical reaction

Ammonia reacts with oxygen to form nitrogen and water. The equation for the balanced chemical reaction is as follows:

4 NH subscript 3 space space plus space space 3 straight O subscript 2 space space rightwards arrow space space 2 straight N subscript 2 space space plus space space 6 straight H subscript 2 straight O

The stoichiometry of the balanced chemical reaction states that four moles of ammonia reacts with three moles of oxygen to form two moles of nitrogen and six moles of water.

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