Nitrogen (N₂) gas and hydrogen (₂) gas react to form ammonia (NH3) gas. Suppose you have 13.0 mol of N₂ and 2.0 mol of H₂ in a reactor. Could half the N₂ react? If you answered yes, calculate how many moles of NH3 would be produced after half the N₂ was used up. Round your answer to the nearest 0.1 mol. O yes O no mol X

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**Reaction of Nitrogen and Hydrogen to Form Ammonia**

Nitrogen (\(N_2\)) gas and hydrogen (\(H_2\)) gas react to form ammonia (\(NH_3\)) gas. Suppose you have 13.0 mol of \(N_2\) and 2.0 mol of \(H_2\) in a reactor.

---

**Could half the \(N_2\) react?**

- \( \circ \) yes
- \( \circ \) no

If you answered yes, calculate how many moles of \(NH_3\) would be produced after half the \(N_2\) was used up. Round your answer to the nearest 0.1 mol.

\(\boxed{} \text{mol}\)

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Transcribed Image Text:**Reaction of Nitrogen and Hydrogen to Form Ammonia** Nitrogen (\(N_2\)) gas and hydrogen (\(H_2\)) gas react to form ammonia (\(NH_3\)) gas. Suppose you have 13.0 mol of \(N_2\) and 2.0 mol of \(H_2\) in a reactor. --- **Could half the \(N_2\) react?** - \( \circ \) yes - \( \circ \) no If you answered yes, calculate how many moles of \(NH_3\) would be produced after half the \(N_2\) was used up. Round your answer to the nearest 0.1 mol. \(\boxed{} \text{mol}\) *Note: The section on the right contains a tool icon indicating interactive functionality, which could be for resetting or accessing additional options.*
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Step 1

Given that nitrogen gas (N2) reacts with hydrogen gas (H2) to form ammonia gas (NH3).

13.0 mol of N2 and 2.0 mol of Hare in a reactor.

Whether half of Nreact or not?.

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