am working on a problem that asks me to find out the acceleration of an object on a ramp, and I have drawn the first image. From it we could clearly see that a = g * sin (theta). But that formula does not work for all a-> because, as shown in the second image when a is larger, it is not a right triangle, so we cannot take a = g * sin (theta) to find a in this example, am I right?
Displacement, Velocity and Acceleration
In classical mechanics, kinematics deals with the motion of a particle. It deals only with the position, velocity, acceleration, and displacement of a particle. It has no concern about the source of motion.
Linear Displacement
The term "displacement" refers to when something shifts away from its original "location," and "linear" refers to a straight line. As a result, “Linear Displacement” can be described as the movement of an object in a straight line along a single axis, for example, from side to side or up and down. Non-contact sensors such as LVDTs and other linear location sensors can calculate linear displacement. Non-contact sensors such as LVDTs and other linear location sensors can calculate linear displacement. Linear displacement is usually measured in millimeters or inches and may be positive or negative.
I am working on a problem that asks me to find out the acceleration of an object on a ramp, and I have drawn the first image. From it we could clearly see that a = g * sin (theta). But that formula does not work for all a-> because, as shown in the second image when a is larger, it is not a right triangle, so we cannot take a = g * sin (theta) to find a in this example, am I right?
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How could the formula be the same? I mean it is not a right triangle.
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