Aluminum sulfate can be made by the following reaction. 2AlCl3(aq) + 3H2SO4(aq) → Al2(SO4)3(aq) + 6HCl(aq) It is quite soluble in water, so to isolate it the solution has to be evaporated to dryness. This drives off the volatile HCl, but the residual solid has to be heated to a little over 200 °C to drive off all of the water. In one experiment, 25.0 g of AlCl3 were mixed with 30.0 g of H2SO4. Eventually, 28.46 g of pure Al2(SO4)3 were isolated. Calculate the percentage yield.
Aluminum sulfate can be made by the following reaction. 2AlCl3(aq) + 3H2SO4(aq) → Al2(SO4)3(aq) + 6HCl(aq) It is quite soluble in water, so to isolate it the solution has to be evaporated to dryness. This drives off the volatile HCl, but the residual solid has to be heated to a little over 200 °C to drive off all of the water. In one experiment, 25.0 g of AlCl3 were mixed with 30.0 g of H2SO4. Eventually, 28.46 g of pure Al2(SO4)3 were isolated. Calculate the percentage yield.
Chemistry
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ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
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Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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Aluminum sulfate can be made by the following reaction.
2AlCl3(aq) + 3H2SO4(aq) → Al2(SO4)3(aq) + 6HCl(aq)
It is quite soluble in water, so to isolate it the solution has to be evaporated to dryness. This drives off the volatile HCl, but the residual solid has to be heated to a little over 200 °C to drive off all of the water. In one experiment, 25.0 g of AlCl3 were mixed with 30.0 g of H2SO4. Eventually, 28.46 g of pure Al2(SO4)3 were isolated. Calculate the percentage yield.
Expert Solution
Step 1
Given :
Mass of AlCl3 = 25g
Mass of H2SO4 = 30g
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