Assuming the reaction stoichiometry is correct, Ka should be the same (within the bounds of experimental error). But if the assumed reaction stoichiometry is incorrect, the equilibrium constant will vary greatly. K = Fe(SCN) Fe(SCN) [Fe³[SCN] If this was the actual reaction, the concentration of Fe(SCN), determined from the absorbance measurements would have been half of the concentration of FeSCN as shown in the table below. Use these new equilibrium concentrations to calculate the equilibrium constant for the reaction above. Consider the following reaction: 3+ Fe³+ + 2 SCN

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Chapter1: Chemical Foundations
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Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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Can you help me with Part 3. U don’t have to answer the table at the bottom
Sample
Number
1
2
3
4
5
Initial moles
Equilibrium moles
Fe³+
SCN
00 18.24
01
-01 4×40.50
.01 6×103 2.19
.01 8x10 3.89
0101 6.64
Fe³+
Equilibrium
Concentration (in M)
SCN FeSCN²
SCN FeSCN²
18.298 18.3 +1.83
0.506.51 .05
2.194 2.2 2,22
3.892 39
·6.04 6.05.0
Fe³+
initial moles
moles od Fest.002.5=.01 moles
Concentration of fe ScN²³:
y=0.374 +0.174
.85-0.37x +0.174
,83 = x
4
39
Calculations
Fe ² (ag) + SCN (ay)<> Fe(SCN) an)
Fe³: My₁ = my SCN²: M₁ V₁ -M₂ √₂
Fest
(2) (10) - (20) M₂
(002) (5) = M₂
20
0.1M - M₂
5+105-1₂
1.83.83
.055
051 201
22 22 045
39
39 0.26
05
1.60
Kea
605
0-17
Concentration
J
Transcribed Image Text:Sample Number 1 2 3 4 5 Initial moles Equilibrium moles Fe³+ SCN 00 18.24 01 -01 4×40.50 .01 6×103 2.19 .01 8x10 3.89 0101 6.64 Fe³+ Equilibrium Concentration (in M) SCN FeSCN² SCN FeSCN² 18.298 18.3 +1.83 0.506.51 .05 2.194 2.2 2,22 3.892 39 ·6.04 6.05.0 Fe³+ initial moles moles od Fest.002.5=.01 moles Concentration of fe ScN²³: y=0.374 +0.174 .85-0.37x +0.174 ,83 = x 4 39 Calculations Fe ² (ag) + SCN (ay)<> Fe(SCN) an) Fe³: My₁ = my SCN²: M₁ V₁ -M₂ √₂ Fest (2) (10) - (20) M₂ (002) (5) = M₂ 20 0.1M - M₂ 5+105-1₂ 1.83.83 .055 051 201 22 22 045 39 39 0.26 05 1.60 Kea 605 0-17 Concentration J
Name
Part III: What if?
Assuming the reaction stoichiometry is correct, Ke should be the same (within the bounds of experimental error). But if the assumed reaction
stoichiometry is incorrect, the equilibrium constant will vary greatly.
Consider the following reaction:
Fe(SCN)
K =
Fe(SCN)
[Fe³][SCN]
If this was the actual reaction, the concentration of Fe(SCN), determined from the absorbance measurements would have been half of the
concentration of FeSCN* as shown in the table below. Use these new equilibrium concentrations to calculate the equilibrium constant for the
reaction above.
Sample
Number
1
3
5
Fe
Initial mols
SCN
Fe +2 SCN=
Fe**
Equilibrium mols
SCN
Fe(SCN)
Equilibrium Concentration
Fe
(M)
SCN
Fe(SCN)
Calculated
Kea
Based on the results above, which of the two possible reactions represents the correct equilibrium? How do you know? Explain.
Transcribed Image Text:Name Part III: What if? Assuming the reaction stoichiometry is correct, Ke should be the same (within the bounds of experimental error). But if the assumed reaction stoichiometry is incorrect, the equilibrium constant will vary greatly. Consider the following reaction: Fe(SCN) K = Fe(SCN) [Fe³][SCN] If this was the actual reaction, the concentration of Fe(SCN), determined from the absorbance measurements would have been half of the concentration of FeSCN* as shown in the table below. Use these new equilibrium concentrations to calculate the equilibrium constant for the reaction above. Sample Number 1 3 5 Fe Initial mols SCN Fe +2 SCN= Fe** Equilibrium mols SCN Fe(SCN) Equilibrium Concentration Fe (M) SCN Fe(SCN) Calculated Kea Based on the results above, which of the two possible reactions represents the correct equilibrium? How do you know? Explain.
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