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- Rewrite the Equations and show work C2H4+ O2−→ CO2+ H2O[References] Calculate AH for the reaction: 2NH3 (g) + O2(g) → N2H4 (1) + H2O(1) given the following data: 2NH3 (g) + 3N2O(g) → 4N2(g) + 3H2O(1) AH =–1010. kJ N2O(9) + ЗH2(9) — N;Ha (1) + Hа0(1) ДН %3D — 317 kJ N2H4 (1) + O2 (9) → N2(g)+2H20(1) ΔΗ--623 k.J На (9) + О2(9) — Н,0(1) AH = -286 kJ ΔΗ- kJ Submit Answer Try Another Version 3 item attempts remainingplease help with the following! I believe the answer can either be 881, -881, or 852
- 18. (a) Molecule N₂H4 (1) + 2 H₂O2 (1) → N2(g) + 4 H₂O (1) Complete the following table: Lewis Dot Structure (use dots or lines to show bonds) (b) (c) (d) N₂H4 H₂O2 N₂ H₂O Calculate the AH°rxn using average bond energies (Table 9.4 in textbook) Calculate the AH°rxn using the standard enthalpies of formation (Appendix 2 in textbook) Why are these two values slightly different?CH,(9) + 2 O,(g) AH = -809.0 kJ/mol Co,(9) + 2 H,O(g) ΔΗ. cond = -81.3 kJ 2 H,0(/) Given the energy diagram above, what is AH when 0.5 mol of methane is combusted? -802.3 kJ +802.3 kJ -1604.6 kJ +401.15 kJ +1604.6 kJ -401.15 kJCalculate the Enthalpy (AH, in kJ/mol) for the following reaction from the heat of rxn formation data given below (Hint: Carefully check the state symbols in this reaction): 4 NO (g) + 6 H20 (I) → 4 NH3 (g) + 5 O2 (g) = ? NH3(g) AH, = - 45.9 kJ/mol NO(g) = + 90.3 kJ/mol H20(1) AH 285.8 kJ/mol = - H20(g) AH = - 241.80 kJ/mol f
- [References] Carbon dioxide from the atmosphere "weathers," or dissolves, limestone (CaCO3) by the reaction CACO3 (s) + CO2(9) + H2O(1) → Ca²* (ag) + 2HCO;¯(ag) Obtain AH for this reaction using the following data: AĦ;(CaCO3 (s)) = -1206.9 kJ/mol %3D AH;(CO2(9)) = -393.5 kJ/mol AH;(H20(1)) = –285.8 kJ/mol AH;(Ca* (aq) =-542.8 kJ/mol %3D AH; (HCO; (ag) = -692.0 kJ/mol AH kJ Submit Answer Try Another Version 6 item attempts remaining Visited4G VOLTE O 76 14 4:58 7 February 2021 4:57 PM (ii) Calculate the lattice energy of Silica oxide (SiO2) from the data given below: Si (g) - Si (s) AH° = -454 kJ mol-1 S1A+ (E) + 4e" Si (3) AH° = -9949 kJ mol-1 20 (g) – 02 (3) AH° = -498 kJ mol-1 02 (3) 0 (g) + 2e AH° = -737 kj mol-1 Si (s) + 02 (3) → SiO2 (s) s14+ (6) - 202- (3) – SiO2 (s) AHf (SIO2)= -910.9 kj mol1 AH°lattice = ? Share Favourite Edit Delete MoreQ No 46 Kindly solve this question correctly in 30 minutes and get the thumbs up please show me neat and clean work for Kindly provide correct solution