Absorption and emission of electronic energy: a) You find two bottles in the lab that have lost their labels. You know that the two compounds are 2,3-dimethyl-1,3-butadiene and 2,5-dimethyl-1,3,5-hexatriene. You find that UV absorbance maxima are at 226 nm and 252 nm. Which spectrum belongs to which compound? How do you know this? H. H CH3 CH₂ H CH₂ b) The (n to *) transition of N=0 has a maximum at 660 nm, while the (a to *) transition in C=C is at 180 nm. Why would the transition for the N=O molecule be at a much longer wavelength? You may wish to use simple HOMO and LUMO energy diagrams for clarity. c) Diamond and graphite are allotropic forms of carbon. Consider the molecular structures shown and the types und Use them to explain why graphite (LEFT) is black while diamonds (RIGHT) are colourless.
Absorption and emission of electronic energy: a) You find two bottles in the lab that have lost their labels. You know that the two compounds are 2,3-dimethyl-1,3-butadiene and 2,5-dimethyl-1,3,5-hexatriene. You find that UV absorbance maxima are at 226 nm and 252 nm. Which spectrum belongs to which compound? How do you know this? H. H CH3 CH₂ H CH₂ b) The (n to *) transition of N=0 has a maximum at 660 nm, while the (a to *) transition in C=C is at 180 nm. Why would the transition for the N=O molecule be at a much longer wavelength? You may wish to use simple HOMO and LUMO energy diagrams for clarity. c) Diamond and graphite are allotropic forms of carbon. Consider the molecular structures shown and the types und Use them to explain why graphite (LEFT) is black while diamonds (RIGHT) are colourless.
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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
Transcribed Image Text:Absorption and emission of electronic energy:
a) You find two bottles in the lab that have lost their labels. You know that the two
compounds are 2,3-dimethyl-1,3-butadiene and 2,5-dimethyl-1,3,5-hexatriene. You
find that UV absorbance maxima are at 226 nm and 252 nm. Which spectrum belongs
to which compound? How do you know this?
H.
H
Segment of
a sheet of
graphite
CH3
CH3
H
b) The (n to *) transition of N=0 has a maximum at 660 nm, while the ( to *) transition in C=C is at 180 nm.
Why would the transition for the N=O molecule be at a much longer wavelength? You may wish to use simple
HOMO and LUMO energy diagrams for clarity.
CH₂
c) Diamond and graphite are allotropic forms of carbon. Consider the molecular structures shown and the types
of bonds. Use them to explain why graphite (LEFT) is black while diamonds (RIGHT) are colourless.
Segment of
a diamond
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