a. Suppose there are two genes - A and B - that specify production of the same enzyme. These two genes show autosomal recessive inheritance. An abnormal phenotype results only if an individual does not make any of that enzyme. Only one of these two genes needs to be functional in order to make the enzyme. What ratio of normal to abnormal progeny would result from a mating between two parents of genotype AaBb - where A and B represent alleles that specify production of the enzyme, while a and b do not?
Duplication of genes is an important evolutionary mechanism. As a result, many, cases are known in which a species has two or more identical genes.
a. Suppose there are two genes - A and B - that specify production of the same enzyme. These two genes show autosomal recessive inheritance. An abnormal phenotype results only if an individual does not make any of that enzyme. Only one of these two genes needs to be functional in order to make the enzyme. What ratio of normal to abnormal progeny would result from a mating between two parents of genotype AaBb - where A and B represent alleles that specify production of the enzyme, while a and b do not?
- Suppose now there are three genes - A,B and C that specify production of this enzyme. Again, these traits show autosomal recessive inheritance. As before, only one single functional gene is sufficient for a wild-type phenotype.
- How many of the possible
phenotypes would be normal? Write your answer as a number
I need help to get the an answer and undertansd please explain it to me and use a punnet square to show work if needed thank you
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