a. Null and alternative hypotheses. b. Possible Type I and Type II errors. c. Level of significance and rejection region.
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- what causes the rejection of null hypothesis? what is the significance level?There are 3 parts to this question The value of the standard score is (round to two decimal places as needed) The critical value(s) is/are (use a comma to separate the answers as needed. Round to two decimal places as needed.) Determine whether the alternative hypothesis is supported at a 0.01 significance level.A type of error that incorrectly rejects the null hypothesis a.Type 1 error b.Type Il error c.Probabilistic error d.Estimation error
- The critical boundaries for a hypothesis test are z = +1.96 and -1.96. If the z-score for the sample data is z =-1.90, what is the correct statistical decision? Reject H0 Fail to reject H1 Reject H1 Fail to reject H0If you reject the null hypothesis ar the 5% significance level would you reject the null hypothesis at the 3% significance level? Group of answer choices yes no not enough information to determine.Differentiate between Type 1 and Type 2 error. What is the null hypothesis and the alternative hypothesis in the American judicial system, and the corresponding type 1 and type 2 errors for these hypotheses? Explain significance level, and which type of error can be controlled by the significance level?
- In an Omani factory, a machine that produces "W-product" has been set so that the true average diameter of the "W-product" it produces is 0.602 in. If its diameter is within 0.04 in. of this target value, this is acceptable. Suppose, however, that the setting has changed during the course of production, so that the products have normally distributed diameters with mean value 0.601 in. and standard deviation 0.002 in. What percentage of the "W-product" produced will not be acceptableTrue or false: The P-value is the smallest significance level for which the observed sample data result in rejection of the null hypothesis.B. Identify the test statistic. ______ C. Identify the P-value. ____ D. What is the conclusion for this test? The P-value is (greater than/less than) the significance level α, so (reject/ fail to reject) the null hypothesis. There is (sufficient/ insufficient) evidence to support the claim that vinyl gloves have a greater virus leak rate than latex gloves.
- K The display provided from technology available below results from using data for a smartphone carrier's data speeds at airports to test the claim that they are from a population having a mean less than 5.00 Mbps. Conduct the hypothesis test using these results. Use a 0.05 significance level. Identify the null and alternative hypotheses, test statistic, P-value, and state the final conclusion that addresses the original claim. Click the icon to view the display from technology. D iew an example Get more help. 42 W S Assuming all conditions for conducting a hypothesis test are met, what are the null and alternative hypotheses? OA. Ho: 5.00 Mbps J D. Ho: -5.00 Mbps H₁: - Clear all : - ; X option F11 { [ ? + = 1 I Check answer F12 } ] delete retu1. Define the critical region for a hypothesis test and explain how we use it to support or reject our null and alternative hypotheses. 2. Identify and explain the influence of the three factors that affect the value of the z-score in a hypothesis test. 3.Identify the steps of a hypothesis test and what additional measure should always be included. 4. Describe the difference between type I and type II errorIdentify the claim and state Ho and H Determine whether the hypothesis test is left-tailed, right-tailed, or two-tailed, and whether to use a z-test, a t-test, or a chi-square test. Explain your reasoning. Find the critical value(s), identify the rejection region(s), and find the appropriate standardized test statistic. Decide whether to reject or fail to reject the null hypothesis. Interpret the decision in the context of the original claim. A government agency reports that the mean amount of earnings for full-time workers ages 25 to 34 with a master’s degree is less than $70,000. In a random sample of 15 full-time workers ages 25 to 34 with a master’s degree, the mean amount of earnings is $66,231 and the standard deviation is $5945. At α = 0.05, is there enough evidence to support the agency’s claim? Assume the population is normally distributed.