9) Determine the decision criterion for rejecting the null hypothesis in the given hypothesis test3;ie., describe the values of the test statistic that would result in rejection of the null hypothesis.Suppose you wish to test the claim that u, the mean value of the differences d for apopulation of paired data, is greater than 0. Given a sample of n= 15 and a significance levelof a= 0.01, what criterion would be used for rejecting the null hypothesis?A) Reject null hypothesis if test statistic <2.624.B) Reject null hypothesis if test statistic > 2.602.C) Reject null hypothesis if test statistic > 2.624.D) Reject null hypothesis if test statistic > 2.977 or < -2.977.%3D

Given information: n = 15 α=0.01

Answered: 9) Determine the decision criterion for…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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Test the claim that the proportion of men who own cats is smaller than the proportion of women who own cats at the .05 significance level. The null and alternative hypothesis would be: Ho: HM = HF H,:PM = PF Ho: HM = PF Ho:HM = Pr Ho:PM = Pr Ho:PM PF H1: HM PF H1:HM > HF H1:HM # HF H1:PM + PF H1:PM < Pf The test is: right-tailed two-tailed left-tailed Based on a sample of 40 men, 40% owned cats Based on a sample of 40 women, 65% owned cats The test statistic is: (to 2 decimals) The p-value is: (to 4 decimals) Based on this we: O Reject the null hypothesis OFail to reject the null hypothesis Check Answer
Test the claim that the proportion of people who own cats is significantly different than 20% at the 0.02 significance level. The null and alternative hypothesis would be: Ho: 0.2 Ho:p 0.2 Ho: 0.2 O O O The test is: left-tailed two-tailed right-tailed O O Ho:p 0.2 of H₁:p> 0.2 H₁: 0.2 H₁ :p < 0.2 O O Based on a sample of 500 people, 22% owned cats The p-value is: (to 2 decimals)
Test the claim that the proportion of men who own cats is significantly different than the proportion of women who own cats at the 0.02 significance level. The null and alternative hypothesis would be: Ho: M = μF Ho: PM = PF H₁ μM μF H₁:PM > PF The test is: left-tailed right-tailed two-tailed Based on a sample of 60 men, 30% owned cats Based on a sample of 40 women, 45% owned cats The test statistic is: Ho: PM = PF H₁: PM μF (to 2 decimals) (to 2 decimals) Ho: PM = PF Ho: M = μF H₁:PM ‡ PF H₁: μM < MF
Test the claim that the mean GPA of night students is significantly different than 3.2 at the 0.2 significance level.The null and alternative hypothesis would be: (multiple choice) H0:p=0.8H0:p=0.8H1:p>0.8H1:p>0.8 H0:μ=3.2H0:μ=3.2H1:μ>3.2H1:μ>3.2 H0:p=0.8H0:p=0.8H1:p<0.8H1:p<0.8 H0:μ=3.2H0:μ=3.2H1:μ≠3.2H1:μ≠3.2 H0:μ=3.2H0:μ=3.2 H1:μ<3.2H1:μ<3.2 H0:p=0.8H0:p=0.8H1:p≠0.8H1:p≠0.8 The test is: (multiple choice) left-tailed right-tailed two-tailed Based on a sample of 30 people, the sample mean GPA was 3.17 with a standard deviation of 0.07The test statistic is: (to 2 decimals)The positive critical value is: (to 2 decimals)Based on this we: (multiple choice) Reject the null hypothesis Fail to reject the null hypothesis
A random sample of 200 students is taken at the University of Ottawa in order to determine the true proportion p who smoke marijuana. It is observed that 130 smoke marijuana. We wish to test Ho p = 0.75 H₁ p < 0.75 at the 0.05 significance level. The value of the test statistic and the decision are -3.27 reject the null hypothesis 3.27 do not reject the null hypothesis 2.45 reject the null hypothesis -2.45 reject the null hypothesis
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Test the claim that the proportion of men who own cats is larger than 20% at the .05 significance level. The null and alternative hypothesis would be: 0.2 Но: р — 0.2 Но: д 0.2 Но:р Но: и Н: + 0.2 Н]:р 0.2 Hi:д > 0.2 Hi:р+0.2 0.2 Но:р — 0.2 Но: д 0.2 The test is: left-tailed two-tailed right-tailed Based on a sample of 25 people, 25% owned cats The test statistic is: (to 2 decimals) The critical value is: (to 2 decimals) Based on this we: O Fail to reject the null hypothesis Reject the null hypothesis
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Test the claim that the proportion of men who own cats is smaller than the proportion of women who own cats at the .005 significance level. The null and alternative hypothesis would be: Ho: PM = PF Ho: MM = F Ho: PM = PF H₁ PM PF H₁: μM μF H₁ PM > PF O O The test is: left-tailed two-tailed O O Based on a sample of 80 men, 25% owned cats Based on a sample of 20 women, 35% owned cats The test statistic is: The p-value is: right-tailed O Based on this we: O Reject the null hypothesis O Fail to reject the null hypothesis Ho: PM = MF H₁: MM > MF (to 2 decimals) (to 2 decimals) Ho: MM = F Ho:PM = PF H₁: MM < MF H₁:PM < PF O O
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Test the claim that the proportion of men who own cats is larger than 20% at the .01 significance level. The null and alternative hypothesis would be: Ho: P 0.2 Hop 0.2 Hoμ = 0.2 H₁: p0.2 H₁ : μ 0.2 (to 2 decimals) (to 2 decimals) Ho: p = 0.2 0 H₁: p < 0.2

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