a. Find the eigenvalues and eigenvectors of the matrix x₁ (t) x₂(t): = X₁ b. Solve the system of differential equations a' = = V₁ = 5 -3 [2] 4 -2 -3 = √²₁ -2] and X₂ = e satisfying the initial conditions V2 x₁ (0) =

Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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**Problem Statement**

a. Find the eigenvalues and eigenvectors of the matrix 
\[
\begin{bmatrix}
5 & -3 \\
4 & -2 
\end{bmatrix}
\]

- Eigenvalue \( \lambda_1 = \underline{\hspace{2cm}} \), 
- Eigenvector \( \mathbf{v}_1 = \begin{bmatrix} \underline{\hspace{1cm}} \\ \underline{\hspace{1cm}} \end{bmatrix} \),

- Eigenvalue \( \lambda_2 = \underline{\hspace{2cm}} \),
- Eigenvector \( \mathbf{v}_2 = \begin{bmatrix} \underline{\hspace{1cm}} \\ \underline{\hspace{1cm}} \end{bmatrix} \)

b. Solve the system of differential equations 

\[
\mathbf{x}' = 
\begin{bmatrix} 
5 & -3 \\ 
4 & -2 
\end{bmatrix} 
\mathbf{x}
\]

satisfying the initial conditions 

\[
\begin{bmatrix}
x_1(0) \\
x_2(0)
\end{bmatrix}
=
\begin{bmatrix}
-2 \\
-3
\end{bmatrix}
\]

- Solution:
  - \( x_1(t) = \underline{\hspace{10cm}} \)
  - \( x_2(t) = \underline{\hspace{10cm}} \)
Transcribed Image Text:**Problem Statement** a. Find the eigenvalues and eigenvectors of the matrix \[ \begin{bmatrix} 5 & -3 \\ 4 & -2 \end{bmatrix} \] - Eigenvalue \( \lambda_1 = \underline{\hspace{2cm}} \), - Eigenvector \( \mathbf{v}_1 = \begin{bmatrix} \underline{\hspace{1cm}} \\ \underline{\hspace{1cm}} \end{bmatrix} \), - Eigenvalue \( \lambda_2 = \underline{\hspace{2cm}} \), - Eigenvector \( \mathbf{v}_2 = \begin{bmatrix} \underline{\hspace{1cm}} \\ \underline{\hspace{1cm}} \end{bmatrix} \) b. Solve the system of differential equations \[ \mathbf{x}' = \begin{bmatrix} 5 & -3 \\ 4 & -2 \end{bmatrix} \mathbf{x} \] satisfying the initial conditions \[ \begin{bmatrix} x_1(0) \\ x_2(0) \end{bmatrix} = \begin{bmatrix} -2 \\ -3 \end{bmatrix} \] - Solution: - \( x_1(t) = \underline{\hspace{10cm}} \) - \( x_2(t) = \underline{\hspace{10cm}} \)
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