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- A physical therapist wanted to know whether the mean step pulse of men was less than the mean step pulse of women. She randomly selected 54 men and 70 women to participate in the study. Each subject was required to step up and down a 6-inch platform. The pulse of each subject was then recorded. The following results were obtained. Two sample T for Men vs Women N Mean StDev SE Mean Men Women 98% CI for mu Men - mu Women (- 12.20, - 1.00) T-Test mu Men = mu Women (vs H2 O C. Ho: H1 = H2; Ha: H1 #H2 (b) Identify the P-value and state the researcher's conclusion if the level of significance was a = 0.01. What is the P-value? P-value =If the test statistic for a right sided test is z = 1.71, then the p-value isSelect one: A.0.9573 B.0.9564 C.0.0436 D.0.0427Use the Student's tt-distribution to find the tt-value for each of the given scenarios. Round tt-values to four decimal places. Find the value of tt such that the area in the right tail of the tt-distribution is 0.0005, if the sample size is 130. t= Find the value of tt such that the area in the left tail of the tt-distribution is 0.01, if the sample size is 123. t= Find the value of tt such that the area in the right tail of the tt-distribution is 0.005, if the sample size is 136. t= Find the two values of tt such that 80% of the area under the tt-distribution is centered around the mean, if the sample size is 96. Enter the solutions using a comma-separated list. t=
- Listed below are the lead concentrations in µg/g measured in different traditional medicines. Use a 0.01 significance level to test the claim that the mean lead concentration for all such medicines is less than 15 µg/g. Assume that the sample is a simple random sample. 9.5 9 17 2.5 9.5 13 13 13 22.5 13 nts ED OC. Ho: p= 15 µg/g OD. Hop=15 µg/g H₁: μ< 15 µg/g H₁ μ#15 µg/g Determine the test statistic. (Round to two decimal places as needed.) Determine the P-value. (Round to three decimal places as needed.). State the final conclusion that addresses the original claim. 15 µg/g. Ho. There is evidence to conclude that the mean lead concentration for all such medicines is Time Remaining: 01:24:16 Next Privacy Policy | Permissions | Contact Us I Terms of Use S ENG O US ess Less Library esources ptions 5 pis Copyright © 2022 Pearson Education Inc. All rights reserved ▬▬ see sc see sc see sco see scoQ.28 onlyGiven in the table are the BMI statistics for random samples of men and women. Assume that the two samples are independent simple random samples selected from normally distributed populations, and do not assume that the population standard deviations are equal. Complete parts (a) and (b) below. Use a 0.05 significance level for both parts. Male BMI Female BMI μ μ1 μ2 n 41 41 x 28.3981 26.4624 s 7.246507 5.820596 a. Test the claim that males and females have the same mean body mass index (BMI). What are the null and alternative hypotheses? A. H0: μ1=μ2 H1: μ1≠μ2 B. H0: μ1≥μ2 H1: μ1<μ2 C. H0: μ1≠μ2 H1: μ1<μ2 D. H0: μ1=μ2 H1: μ1>μ2 The test statistic, t, is ______.(Round to two decimal places as needed.) The P-value is _____.(Round to three decimal places as needed.) State the conclusion for the test. A. Fail to reject the null…
- I randomly sample 219 students and ask them to provide their USF GPA. I wish to determine if the average GPA of all USF students ex mu + 3.25 ceeds 3.25. Unfortunately, I generated the printout shown here: One-Sample T Test Null Hypothesis: H - 3.25 Alternative Hyp: u- 3.25 Variable Mean SE DF GPA 3.3121 0.0340 1.82 218 0.0694 Cases Included 219 What assumption is needed for this analysis to be valid? None. The Central Limit Theorem applies and no other assumptions are needed. The GPAS of all USF students need to be approximately normally distributed The mean GPA of all USF students need to be approximately normally distributedQ1-5: Given the following data from a sample of sizen= 7 12 7 49073 The third qoartile is: Select one: O a. 4 O b. 7 O c. 8 O d. 9The following information is available for two samples selected from independent normally distributed populations. Complete parts (a) and (b). s? = 57.3 s2 = 20.6 Population A: n= 13 Population B: n= 21 a. At the 0.05 level of significance, is there evidence of a difference between of and o3? Determine the hypotheses. Choose the correct answer below. O A. Ho of = 03 O B. Ho, o7 so? O D. Ho; o7 +o3 OC. Họ; o7 203 H,: of o?? What is your statistical decision? The upper-tail critical value of F is (Round to two decimal places as needed.) What is your statistical decision? V Ho. There is V evidence that o? >o3.
- Children with autism differ significantly from children without autism on tests of varbal ability. repeated measures? or ind. with two tails?For a two-tailed test with a sample size of 17 and a 0.20 level of significance, the t value is O a. 1.337 O b. 0.865 O c. 1.230 d. 1.734 OIn a 4-week study about the effectiveness of using magnetic insoles to treat plantar heel pain, 58 subjects wore magnetic insoles and 40 subjects wore nonmagnetic insoles. The results are shown at the right. At a= 0.06, can you support the claim that there is a difference in the proportion of subjects who feel better between the two groups? Assume the random samples are independent. Complete parts (a) through (e). Do you Feel Better? Magnetic Insoles I Yes 20 I No 38 Nonmagnetic Insoles Yes 17 No 23 (Use a comma to separate answers as needed. Type an integer or a decimal. Round to two decimal places as needed.) Identify the rejection region(s). Select the correct choice below and fill in the answer box(es) within your choice. (Round to two decimal places as needed.) O A. z O B. z> O D. z< C. (c) Find the standardized test statistic. (Round to two decimal places as needed.) (d) Decide whether to reject or fail to reject the null hypothesis Choose the correct answer below.