8. Measurements are made on the lengths, in mm. of a sample of twenty woodencomponents for self-assembly furniture. Assume that these may be regarded as twentyindependent observations from a normal distribution with unknown mean u and unknownvariance o2. The data are as follows.581 580 581 577 580581 577 579 579 578581 583 577 578 582 581 582 580 582 579Find a 95% confidence interval for the standard deviation o.A.B.C.D.1.942

The given data is 581 580 581 577 580 581 577 579 579 578 581 583 577…

Answered: 581 580 581 577 580 581 577 579 581 583…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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Construct a confidence interval of the population proportion at the given level of confidence. x= 120, n= 1100, 95% confidence Click here to view the standard normal distribution table (page 1). Click here to view the standard normal distribution table (page 2). The lower bound of the confidence interval is (Round to three decimal places as needed.) The upper bound of the confidence interval is (Round to three decimal places as needed.)
pls answer a with some explanation tq
(d) Why is the margin of error for this confidence interval so small? O A. The standard deviation is very small. OB. The sample size used is very large. OC. The mean is very small. O D. The standard deviation is very large. ہے
In order to determine the true mean pulse rate of New York citizens you take a sample of 16 and the sample mean is 72 with a standard deviation of 9 beats per minute. Based on this data, the 95% confidence interval for the true mean pulse rate of New York Citizens is 72 plus or minus________?
acc1
Pavan
Construct a confidence interval for p, - p, at the given level of confidence. X1 = 398, n1 = 543, x2 = 408, n2 = 578, 99% confidence The researchers are % confident the difference between the two population proportions, p, - p2, is between and (Use ascending order. Type an integer or decimal rounded to three decimal places as needed.)
A sample of 230 observations is selected from a normal population with a population standard deviation of 22. The sample mean is 17. a) Determine the standard error of the mean. (Round your answer to 3 decimal places.) b) Determine the 95% confidence interval for the population mean. (Use z Distribution Table.) (Round your answers to 3 decimal places.) confidence interval _____________ and______________
Construct a confidence interval for P₁-P₂ at the given level of confidence. X₁ = 369, n₁ = 508, X₂ = 426, n₂ = 599, 95% confidence % The researchers are confident the difference between the two population proportions, P₁-P₂, is between and (Use ascending order. Type an integer or decimal rounded to three decimal places as needed.)
A random sample of 25 people spent an average of 45 minutes having lunch. a. Assume the population standard deviation (?) is known and equals 10, find a 95% confidence interval for the population mean (μ) b. Assume the population standard deviation (?) is unknown and the sample standard deviation (s) equals 10, find a 95% confidence interval for the population mean (μ)
Confidence Interval A simple random sample of 56 students who picked up all tests they completed was selected, and the mean score on final exam for this sample of students was 83 with a standard deviation of 10.4. An independent simple random sample of 51 students who had one or more tests that were not picked up was selected, and the mean score on the final exam for this sample of students was 67 with a standard deviation of 24.2. Both distributions are skewed heavily to the left [note: this is the same information provided in question above]. If appropriate, use this information to calculate and interpret a 99% confidence interval for the difference in the mean score on the final exam for all students who picked up all their tests and the mean score on the final exam for all students who had one or more tests that were not picked up. 16 Are the assumptions met? No, because the distributions are heavily skewed to the left. Yes, because both samples are larger than 40 and there are 2…
Construct a confidence interval for P₁ P2 at the given level of confidence. x₁ = 391, n₁ =529, x₂ = 421, n₂ = 577, 90% confidence The researchers are % confident the difference between the two population proportions, p₁ - P2, is between and (Use ascending order. Type an integer or decimal rounded to three decimal places as needed.)

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581 580 581 577 580 581 577 579 581 583 577 578 582 581 582 580 a 95% confidence interval for the standard deviation o. 579 578 582 579